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3 years ago

Can someone PLEASE HELP thank you!!!

Mathematics

1 answer:

lawyer [7]3 years ago

4 0

Answer:

12.7 yards

Step-by-step explanation:

not sure but that's what I got

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Alguém me ajuda rapido por favor tou aki rachando a cuca e n consigo

Lady bird [3.3K]

The vertices of a right triangle are (–6, 4), (0, 0), and (x, 0). Find the value of x.

4 0

4 years ago

If ƒ(x) = x − 4 and g(x) = 3x + 5, find (ƒ + g)(x).

siniylev [52]

Answer:

$(f+g)(x)=4x+1$

Step-by-step explanation:

We are given the two functions:

$f(x)=x-4\text{ and } g(x)=3x+5$

And we want to find:

$(f+g)(x)$

This is equivalent to:

$=f(x)+g(x)$

By substitution:

$=(x-4)+(3x+5)$

Rearranging yields:

$=(x+3x)+(-4+5)$

Combine like terms:

$=4x+1$

Hence:

$(f+g)(x)=4x+1$

7 0

3 years ago

Read 2 more answers

Use a composite figure to estimate the area of the figure.

bezimeni [28]

A) about 14 square units

You have 11 fully filled squares 2 that are mostly filled and 2 that are about half filled

So 11+2+2(1/2)= about 14

6 0

2 years ago

Read 2 more answers

Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'

AleksandrR [38]

Let's start by assuming Armando's house is between Joey's and the park.

Let $x$ be the distance Joey walked to Armando's house.

<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.

</span> $\dfrac{9}{10} = x + \dfrac{3}{5}$

$x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}$

That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)

Let $a, b, c$ be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

$\pm a \pm b = \pm c$

Let's get rid of the plus/minuses. Squaring,

$a^2 + b^2\pm 2ab = c^2$

$\pm 2ab = c^2-a^2-b^2$

$4a^2b^2 = (c^2-a^2-b^2)^2$

For us, that's a quadratic equation for $c^2$

$4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2$

I'll skip right to the solutions,

$c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}$

$c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}$

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

6 0

4 years ago

Can you please answer this question

Nat2105 [25]

Answer:

1. b

2. a

3. d

4. c

Step-by-step explanation:

3 0

3 years ago