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Sergio [31]
3 years ago
9

Por que razón los números fraccionarios y decimales no tienen un sucesor y un antecesor​

Mathematics
1 answer:
stepan [7]3 years ago
3 0

Answer:

ummmm what did he sayyyyyyyyy

Step-by-step explanation:

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two angles in a triangle mesaure 65 degrees and 75 degrees what is the measure of the third angle of the triangle
podryga [215]

Answer:

40°

Step-by-step explanation:

The interior sum of a triangle is 180°.  Since we have two known angles we will subtract those values from 180 to obtain our third angle and so:

180°-65°-75°=40°


8 0
3 years ago
Find the slope of the line passing through the two points.
pogonyaev
Formula for slope: y2-y1/x2-x1
Plug in values. 
3-8/-4-(-7)= -5/3 = slope
42-1/36-12=41/24=slope
6 0
4 years ago
Help...........................
umka21 [38]

It has a ratio of 1:4, meaning for every x, you'd get 4 from your y

7 0
2 years ago
Read 2 more answers
Combining like terms and simplifying an equation, what is 8a-6+a-1
Sedbober [7]

Answer:

9a-7

Step-by-step explanation:

8a-6+a-1

Collect like terms

8a+a-6-1

= 9a-7

8 0
2 years ago
Which of the values shown are potential roots of f(x) = 3x3 â€"" 13x2 â€"" 3x 45? Select all that apply.
Verdich [7]

The potential roots of the function are, \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}

And the accurate root is 3 it can be determined by using rules of the rational root equation.

<h2>Given that,</h2>

Function; \rm f(x) = 3x^3 - 13x^2 -3x + 45

<h3>We have to determine,</h3>

Which of the values shown are potential roots of the given equation?

<h3>According to the question,</h3>

Potential roots of the polynomial are all possible roots of f(x).

\rm f(x) = 3x^3 - 13x^2 -3x + 45

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

\rm p=\dfrac{All\  the \ positive}{Negative\  factors \ of\  45}

\rm q=\dfrac{All\  the \ positive}{Negative\  factors \ of\  3}

The factor of the term 45 are,

\pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45

And The factor of 3 are,

\pm1, \ \pm3

All the possible roots are,

\dfrac{p}{q} = \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}

Now check for all the rational roots which are possible for the given function,

\rm f(x) = 3x^3 - 13x^2 -3x + 45\\\\ f(1) = 3(1)^3 - 13(1)^2 -3(1) + 45 = 3-13-3+45 = 32\neq 0\\\\ f(-1) = 3(-1)^3 - 13(-1)^2 -3(-1) + 45 =- 3-13+3+45 = 32\neq 0\\\\ f(3) = 3(3)^3 - 13(3)^2 -3(3) + 45 = 81-117-9+45 =0\\\\ f(-3) = 3(-3)^3 - 13(-3)^2 -3(-3) + 45 = -81+117+9+45 =-144\neq 0

Therefore, x = 3 is the potential root of the given function.

Hence, The potential roots of the function are, \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}.

For more details about Potential roots refer to the link given below.

brainly.com/question/25873992

8 0
2 years ago
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