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Semmy [17]
3 years ago
10

If you were trying to decide whether to take out an auto loan for $6500 to buy your first car, thereby allowing you to commuto f

or an impressive summer internship program next year, would that loan meet the requirements?
Mathematics
1 answer:
notka56 [123]3 years ago
4 0

Answer:

Yes, a loan would meet our requirement to commute for an impressive summer internship program next year  

Step-by-step explanation:

Taking a loan would meet our requirement of buying a car. We will be able to make the downpayment. This will enable us to buy a car. So the decision to take the loan will be valid. It will help us in commuting easily for the summer internship program. We will immediately get the car after making a down payment and will avail of the benefits of using the car. This is a healthy type of debt.

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jayden and carson are selling t-shirts and sweatshirts for a fundraiser. jayden sells 9 t-shirts and 3 sweatshirts for $288. car
Genrish500 [490]

Answer:

sweatshirts cost $42

t-shirts cost $18

Step-by-step explanation:

9x+3y=288

x+6y=270

substitute 270-6y for x in the first problem

9(270-6y) +3y=288

2430-54y+3y=288

2430-51y=288

51y=-2142

y=42

then plug y=42 into the second equation

x+6(42)=270

x+252=270

x=18

3 0
3 years ago
What 17 multiply and adds to get -2
Marrrta [24]
17 * 0 + -2.

Now we rewrite the equation and make it 17 * 0 - 2 and u get -2.
8 0
3 years ago
Read 2 more answers
Given f (x) = x2 + 4x + 5, what is f of the quantity 2 plus h end quantity minus f of 2 all over h equal to?
meriva

By evaluating the quadratic function, we will see that the differential quotient is:

\frac{f(2 + h) - f(2)}{h} = 8 + h

<h3>How to get (f(2 + h) - f(2))/h?</h3>

Here we have the quadratic function:

f(x) = x^2 + 4x + 5

Evaluating the quadratic equation we get:

\frac{f(2 + h) - f(2)}{h}

So we need to replace the x-variable by "2 + h" and "2" respectively.

Replacing the function in the differential quotient:

\frac{(2 + h)^2 + 4*(2 + h) + 5 - (2)^2 - 4*2 - 5}{h} \\\\\frac{4 + 2*2h + h^2 + 8 + 4h  - 4 - 8 }{h} \\\\\frac{ 2*2h + h^2  + 4h   }{h} = \frac{8h + h^2}{h}

If we simplify that last fraction, we get:

\frac{8h + h^2}{h} = 8 + h

The third option is the correct one, the differential quotient is equal to 8 + 4.

If you want to learn more about quadratic functions:

brainly.com/question/1214333

#SPJ1

8 0
2 years ago
Numbers 11-14 pls I’m having a lot of trouble
Ksivusya [100]

The term "closed" in math means that if you take two items from a set, do some operation, then you'll always get another value in the same set (sometimes you may get the same value as used before). For example, adding two whole numbers leads to another whole number. We therefore say "the set of whole numbers is closed under addition". This applies to integers as well because integers are positive and negative whole numbers. So we can say that integers are closed under addition.

Integers are not closed under division. Take two integers like 2 an 5 and divide: 2/5 = 0.4 which is not an integer. Integers don't have decimal parts.

The set of whole numbers is {0,1,2,3,...} and we can subtract the two values 1 and 2 to get 1-2 = -1. The order matters here. Subtracting a larger value from a smaller leads to a negative. The value -1 is not in the set of whole numbers. So we can say that whole numbers is not closed under subtraction

Finally, the set of irrational numbers is closed under addition. Adding any two irrational numbers leads to another irrational number. For instance, pi+sqrt(2) = 3.142 + 1.414 = 4.556; I'm using rounded decimals as approximate values. An irrational number is one where we cannot write it as a fraction of integers. Contrast that with a rational number in which we can write it as a fraction of integers. Example: 10 = 10/1 is a rational number.

6 0
3 years ago
My Homework Mr Thompson please help!!
Nady [450]

Answers:

  1. C) Factored form
  2. C) Standard form
  3. D) The y intercept is -8
  4. B) Two solutions: x = -5 or x = 5
  5. B) Apply square root to both sides

=========================================

Explanations:

  • For problems 1 and 2, there's not much to say other than you'll just have to memorize those terms. Standard form is ax^2+bx+c in general. The exponents count down 2,1,0. Factored form is where we have two or more factors multiplying with each other. Think of something like 21 = 7*3 showing that 7 and 3 are factors of 21.
  • For problem 3, the y intercept is the last value. It's the constant value. Plug in x = 0 and you'll get y = -8 as a result. The y intercept always occurs when x = 0.
  • In problem 4, we apply the square root to both sides to get x = -5 or x = 5. The plus or minus is needed. This is because (-5)^2 = 25.
  • In problem 5, we apply the square root to both sides to undo the squaring operation.
4 0
3 years ago
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