If you were trying to decide whether to take out an auto loan for $6500 to buy your first car, thereby allowing you to commuto f
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PART A
The equation of the parabola in vertex form is given by the formula,
where
is the vertex of the parabola.
We substitute these values to obtain,
The point, (3,6) lies on the parabola.
It must therefore satisfy its equation.
Hence the equation of the parabola in vertex form is
PART B
To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.
This implies that
We expand to obtain,
This will give us,
This equation is now in the form,
where
This is the standard form
The equation of the parabola in vertex form is given by the formula,
where
is the vertex of the parabola.
We substitute these values to obtain,
The point, (3,6) lies on the parabola.
It must therefore satisfy its equation.
Hence the equation of the parabola in vertex form is
PART B
To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.
This implies that
We expand to obtain,
This will give us,
This equation is now in the form,
where
This is the standard form
(You go from left to right)
(Dividend is 931, divisor is 7)
Step 1: Look for a number smaller than 9 that is divisible by 7. 7 is the only one which is smaller than 9 and is divisible by 7. Now that you know 7*1=7, you put 1 above 931 (Dividend)
Step 2: You subtract that number from the number in tens place. And bring the leftover down.
Step 3: You repeat Step 1 and 2 until either you get a remainder of 0 or the remainder in smaller than the divisor (in this case 7)
(Therefore 931/7=133, quotient=133, remainder=0)
^Hope this helps.
(Dividend is 931, divisor is 7)
Step 1: Look for a number smaller than 9 that is divisible by 7. 7 is the only one which is smaller than 9 and is divisible by 7. Now that you know 7*1=7, you put 1 above 931 (Dividend)
Step 2: You subtract that number from the number in tens place. And bring the leftover down.
Step 3: You repeat Step 1 and 2 until either you get a remainder of 0 or the remainder in smaller than the divisor (in this case 7)
(Therefore 931/7=133, quotient=133, remainder=0)
^Hope this helps.
Answer:
- 5n square root 5
- 6 square root 6v
- 16ki square root 2
- 10m square root m
- 4p square root 5p
- 3pi square root 5
