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svetoff [14.1K]
3 years ago
8

You move left 4 units and right 3 units. You end at (-2, -1). Where did you start?

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
6 0

Answer:

-2 y

Step-by-step explanation:

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Simplify the expression (3 - 4i)(1 + 5i) - (2 - i). Show your work please! I have the answer: 21 + `12i but I need to show my wo
masha68 [24]

Answer:

21+12i i hope this will help you

Step-by-step explanation:

(3-4i)(1+5i)-(2-i)

=[3(1+5i)-4i(1+5i)]-(2-i)

=[3+15i-4i-20i²]-(2-i)

=(3+11i-20i²)-(2-i)

opening brackeys

=3+11i-20i²-2+i

=3+11i+1i-20i²-2

as we know that i²=-1

=3-20(-1)-2+12i

=3+20-2+12i

=21+12i

8 0
3 years ago
Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno
Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

a) P(X>np+3\sqrt{np(1-p)}=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

P(Y>1)=1-0.349=0.651

3 0
3 years ago
The ratio of the length to the width of a rectangle is 5:4. The length of the rectangle is 60 inches. What is the width?
Firlakuza [10]

\huge\boxed{\text{48 inches}}

We know that \frac{\text{length}}{\text{width}} = \frac{60}{\text{width}} = \frac{5}{4}.

Solve using cross multiplication of the last two fractions. I will use w to represent the width of the rectangle. 60*4=w*5

Multiply. 240=5w

Divide both sides of the equation by 5. \boxed{48}=w

7 0
3 years ago
Read 2 more answers
When patterning a shotgun, what is a sufficient percentage of pellets within a 30-inch circle?.
schepotkina [342]
55% to 60%
The pattern of pellets within a 30-inch circle should be of a proper, even density to ensure a clean kill. The pattern should contain a sufficient percentage of the load, which should be at least 55% to 60%.
8 0
2 years ago
The loudness, L, of a sound (measured in decibels, dB) is inversely proportional to the square of the distance, d, from
kifflom [539]

Answer:

The jetski is 2.28 dB loud when the person is 41 feet away.

Step-by-step explanation:

Loudness (L) ∝ 1 / Distance² (d²)

Introduce a constant 'K'

L = K (1/d²)

L = K/d²

K = Ld²

Find the K from a previously known information: If a person 8 feet from a jetski hears 60 decibels loud

∴ d = 8 ft , L = 60 db

K = 60(8²) = <em>3840</em>

How loud is the jetski when the person is 41 feet away?

Distance is now 41 ft

since: L = K/d²

∴ L = 3840 / 41²

L = 3840 / 1681

L = 2.28 db

3 0
3 years ago
Read 2 more answers
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