Answer:
P and Q are two points on the line x-y+1=0 and are at a distant of 5 units from the origin. Find the area of triangle POQ.
Step-by-step explanation:
P and Q are the intersection points of
x-y+1 = 0 and the circle x^2 + y^2 = 25
sub y = x+1 into the circle
x^2 + (x+1)^2 = 25
x^2 + x^2 + 2x + 1 - 25 = 0
x^2 + x - 12 = 0
(x+4)(x-3) = 0
x = 3 or x = -4
y = 4 or y = -3
so P(3,4) and Q(-4,3) are our two points
Height of triangle.
h = |0 - 0 + 1|/√2 = 1/√2
PQ = √( (-7)^2 + 1^2) = √50 = 5√2
area POQ = (1/2)(1/√2)(5√2) = 5/2 square units
hope this helped
Answer:
Lets solve this algebraically
25 is what troy has.
Caitlin has $55
Step-by-step explanation:
x+2x+5=80 3x=75 x=25
Answer:
t>28
Step-by-step explanation:
t/4>7
t>4×7=28
1/2 * 2/2 = 2/4 which is not 2/7
2/1 * 7/7 = 14/7 which is not 7/14
1/2 * 7/7 = 7/14 which is 7/14 yes
2/1 * 7/7 = 14/7 which is not 14/21 no
Choice C
p = pennies
q= quarters
p = 2q+5 (1)
.25q+.01p=1.67 (2)
substitute the equation for pennies (1) into the 2nd equation
.25q+.01(2q+5)=1.67
distribute
.25q +.02q +.05 = 1.67
combine like terms
.27q +.05 =1.67
subtract .05 from each side
.27q = 1.62
divide by .27
q=6
p=2q+5
p=2(6)+5
p=12+5
p=17
There are 6 quarters and 17 pennies
