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earnstyle [38]
2 years ago
12

(Brainliest) PLEASE HELP PLEASE

Mathematics
2 answers:
Sindrei [870]2 years ago
5 0

Answer: with what

Step-by-step explanation:

lesantik [10]2 years ago
4 0

what's the question?

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kipiarov [429]

Answer:

              s

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ls^4 + 32ls^2 + 256l

Step-by-step explanation:

I used an algebra calculator called MathPapa to solve your equation.

Also, welcome to brainly!

7 0
2 years ago
56· 328+162· 44+166· 44−x =0<br> find x<br> the dot is to mutiply
Slav-nsk [51]

Answer:

x = 32800

Step-by-step explanation:

56 × 328 + 162 × 44 + 166 × 44 - x = 0

18368 + 7128 + 7304 − x = 0

32800 - x = 0

-x = -32800

x = 32800

8 0
2 years ago
Read 2 more answers
(Y+3)(y^2-3y+9)<br><br> A. Y^3+27<br> B. Y^3-27<br> C. Y^3-6y^2+27<br> D. Y^3+6y^2+27
KonstantinChe [14]

Answer:

A) y^3+27

Step-by-step explanation:

There are two ways of solving this problem:

1. Recognizing this as the factored form of the sum of perfect cubes

2. Distribute and add the like terms.

1. In order to distribute we must multiply y by y^2-3y+9, and then 3 by y^2-3y+9:

(y+3)(y^2-3y+9)=y(y^2-3y+9)+3(y^2-3y+9)

y(y^2-3y+9)+3(y^2-3y+9)=y^3-3y^2+9y+3y^2-9y+27

After we add the positive and negative 3y^2 and 9y, they will cancel out and be gone entirely:

y^3-3y^2+9y+3y^2-9y+27=y^3+27

2. You know how you can factor the difference of perfect squares?

As an example:

a^2-b^2=(a+b)(a-b)

Well, not many people know this but you can actually factor both the sum and difference of perfect cubes:

a^3+b^3=(a+b)(a^2-ab+b^2)

a^3-b^3=(a-b)(a^2+ab+b^2)

Because we have these identities, we can easily establish here that we have the sum of perfect cubes, and that (y+3)(y^2-3y+9)= y^3+3^3 = y^3+27

6 0
2 years ago
Find x ÷ y, if x = 3 5/8 and y = 3 3/4 . Express your answer in simplest form.
svetoff [14.1K]
\dfrac{3\frac{5}{8}}{3\frac{3}{4}}=\dfrac{(\frac{29}{8})}{(\frac{15}{4})}=\dfrac{29}{8}\dfrac{4}{15}\\\\=\dfrac{29}{30}

   x ÷ y = 29/30

_____
A suitable calculator can do this for you.

8 0
3 years ago
F(x)=x^2. What is g(x)?
Troyanec [42]
Use “desmos” for the graph
8 0
3 years ago
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