What is the surface area of a triangular based pyramid with a slant height of 8 and a base length of 5? Rounded to the nearest h
1 answer:
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Parameterize by the vector function
so that the normal vector to is given by
with magnitude
In this case, the normal vector is
with magnitude . The integral of
over
is then
where is the region in the
plane over which
is defined. In this case, it's the triangle in the plane
which we can capture with
and
, so that we have
Answer:
y= x-4
Step-by-step explanation:
Since we have a point, and the slope, we can use the point slope formula
m is the slope, y1 is the y coordinate of the point and x1 is the x coordinate of the point.
We know that m is 1, y1 is 1, and x1 is 5, so we can substitute them in
y-1=1(x-5)
Solve for y by isolating it
Distribute the 1
y-1=1*x+ 1*-5
y-1=x-5
Add 1 to both sides
y=x-4