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Afina-wow [57]
3 years ago
5

Solve the following system word problem.

Mathematics
2 answers:
a_sh-v [17]3 years ago
7 0
Let p be the cost of a pizza, and b the cost of a burger.
3p + 6b = 43.41
2p + 7b = 40.91
Take twice the first and subtract from three times the second.
9b = 35.91
b = 3.99
Substitute b back in either equation, to get p = 6.49.
Marizza181 [45]3 years ago
3 0

Answer:

burger =$3.99

pan pizza =$6.49

Step-by-step explanation:

3p+6b=43.41⇒eqn 1

2p+7b=40.91⇒eqn 2

eqn 1 * 2

6p+12b=86.82⇒eqn 3

eqn 2 * 3

6p+21b=122.73⇒eqn 4

eqn 4- eqn 3

9b=35.91

b=3.99

sub b=3.99 in eqn 1

3p=43.41-23.94

p=19.47/3

p=6.49

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