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3 years ago

Ive been doing this for hours please help (answer in mixed number fraction)

Mathematics

1 answer:

frutty [35]3 years ago

4 0

The other person correct i just wanted to confirm i didnt want to copy but yes. so answer is what his answering is

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Which is greater 10.2 or 10.02

Brrunno [24]

10.2 is the right answer 10 dollars and 20 cents is more then 10 dollars and 02 cents

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3 years ago

Read 2 more answers

Please answer math question

slavikrds [6]

Answer:

y = -4x + 9

O.R. y = 9- 4x

(both answers are equivalent, the same)

Step-by-step explanation:

1. finding gradient of perpendicular line to the equation given.

2. use the point provided in the wuestion and substitute it into the linear form of your slope-intercept form, which in my country is called the linear form, meaning straight line graph.

3. get answers by finding the y-intercept of the equation wanted.

note:

y = mx + c is how and what i use in my school as the linear form, altho every school is different and I understand that, so do check again with your teacher if it is how you do such type of questions.

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3 years ago

Sebastian ran 8.64 miles in 2.4 hours at a steady pace.

serg [7]

Sebastian ran 1.44 miles in the last 24 minutes. First, divide 8.64 by 2.4 to get 3.6 miles per hour. Since the question is asking for the last 24 minutes, divide 3.6 by 60 which gives you 0.06. Then, just multiply the rate per minute by 24 which gives you how many miles he ran in the last 24 minutes of his run.

6 0

3 years ago

Please help! Easy 10 points!

nalin [4]

3,168 different committees. <span />

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3 years ago

F=e−yi−xe−yj is conservative. find a scalar potential f and evaluate the line integral over any smooth path c connecting a(0,0)

Alexxx [7]

If $\mathbf F$ is conservative, then there is a scalar function $f$ such that

$\nabla f(x,y)=\mathbf F(x,y)\iff\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j=e^{-y}\,\mathbf i-xe^{-y}\,\mathbf j$

Setting the first components equal to one another, we can integrate both sides to find

$\dfrac{\partial f}{\partial x}=e^{-y}\implies f(x,y)=xe^{-y}+g(y)$

Differentiating both sides with respect to $y$ gives

$\dfrac{\partial f}{\partial y}=-xe^{-y}+\dfrac{\mathrm dg}{\mathrm dy}=-xe^{-y}$
$\implies\dfrac{\mathrm dg}{\mathrm dy}=0$
$\implies g(y)=C$

so that

$f(x,y)=xe^{-y}+C$

By the fundamental theorem of calculus, we have that

$\displaystyle\int_{\mathcal C}\mathbf F\cdot\mathrm d\mathbf r=\int_{\mathcal C}\nabla f\cdot\mathrm d\mathbf r=f(1,1)-f(0,0)=\frac1e$

4 0

3 years ago