The question is not completed
there is some numbers mising
Consider the factors of 40: ±1, ±4, ±10, ±5, ±8 ... ±5 and <span>±8 can be manipulated to fit your factorization.
(x - 8)(x - 5) works. -8 - 5 = -13, which is what you need in the middle, and -8*-5 gives you a positive 40.</span>
You need to <span>draw the diagram to understand the problem easily. Teh diagram will show the right triangle, acute angle with the base 7º, height is 663 m, and "x" is the base of the triangle.
using the tangent ratio:
tan</span>Θ = opposite / adjacent
<span>
tan7º = 663 m / x
x = 663 m / tan7º
x = 5,399.7 m
change m to km. 1,000 m = 1km
5,399.7m * 1km/1,000 m = 5,399.7 km/1000 = 5.3997 km or 5.4 km
B. 5.4 km </span>
Inscribed angles are pretty easy, they're always half the corresponding central angle. The arc measure are always of central angles.
1. We're told to arc is 62 degrees so the inscribed angle is half,
WXY = 31 degrees.
2. Here we're told the inscribed angle is 113 degrees so the arc is double,
DGF=226 degrees
3. Angles which subtend a diameter are always right angles.
PQR = 90 degrees
4. If we draw DC we see it's a radius too, so DC=DB and we have an isosceles triangle so DCB=47 degrees so BDC=180-47-47=86. The central angle is the arc measure so
BC=86 degrees
5. Angle JNK=53 degrees and angles NJK=NKJ because we have an isosceles triangle, two sides radii. So NKJ=(180-53)/2.
Similarly NKL=(180-65)/2
So angle JKL=NKJ+NKL=180 - (65+53)/2 = 180 - 118/2 = 121 degrees
I better leave the rest for you.
(2, 0°) is already in polar coordinates, with the smallest possible angle. The radius is 2, always 2. Expressions with variations of the angle are also good representations of (2, 0°) if their angles are all integer multiples of 360 degrees. For example: (2, 720°) represents the same point in polar coordinates as does (2, 0°).
