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2 years ago

The rate of U.S. per capita sales of bottled water for the period 2000-2010 can be approximated by

Mathematics

1 answer:

melomori [17]2 years ago

5 0

Your answer is simple really just use those multiplying fractional answers to additionally add any remainder properties

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Please help!! I need all I can get!!

LuckyWell [14K]

Answer:

x = 13

Step-by-step explanation:

6x + 14 + 4x - 8 + 2x + 18 = 180 {Angle sum property of tiangle}

6x + 4x + 2x + 14 - 8 +18 = 180 {Combine like terms}

12x + 24 = 180 {Subtract 18 from both sides}

12x = 180 - 24

12x = 156 {Divide both sides by 12}

x = 156/12

x = 13

3 0

2 years ago

Could anyone help me with these questions ASAP?

FrozenT [24]

8 is b because a circle is 360.

5 0

2 years ago

Round 810662.2 to 2 significant figure

Thepotemich [5.8K]

Answer:

810000

Step-by-step explanation:

use 2 nonzero numbers but without the decimal for rounding

7 0

3 years ago

Read 2 more answers

The equation giving a family of ellipsoids is u = (x^2)/(a^2) + (y^2)/(b^2) + (z^2)/(c^2) . Find the unit vector normal to each

Fynjy0 [20]

Answer:

$\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

Step-by-step explanation:

Given equation of ellipsoids,

$u\ =\ \dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}$

The vector normal to the given equation of ellipsoid will be given by

$\vec{n}\ =\textrm{gradient of u}$

$=\bigtriangledown u$

$=\ (\dfrac{\partial{}}{\partial{x}}\hat{i}+ \dfrac{\partial{}}{\partial{y}}\hat{j}+ \dfrac{\partial{}}{\partial{z}}\hat{k})(\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2})$

$=\ \dfrac{\partial{(\dfrac{x^2}{a^2})}}{\partial{x}}\hat{i}+\dfrac{\partial{(\dfrac{y^2}{b^2})}}{\partial{y}}\hat{j}+\dfrac{\partial{(\dfrac{z^2}{c^2})}}{\partial{z}}\hat{k}$

$=\ \dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}$

Hence, the unit normal vector can be given by,

$\hat{n}\ =\ \dfrac{\vec{n}}{\left|\vec{n}\right|}$

$=\ \dfrac{\dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}}{\sqrt{(\dfrac{2x}{a^2})^2+(\dfrac{2y}{b^2})^2+(\dfrac{2z}{c^2})^2}}$

$=\ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

Hence, the unit vector normal to each point of the given ellipsoid surface is

$\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

3 0

3 years ago

In AABC, AB = 2 and AC = 11. Find m2C to the nearest degree.<br>help please

AlexFokin [52]

Answer:

Step-by-step explanation:

<h3>Calculating BC</h3><h3>BC = √2^2 + 11^2 </h3><h3>BC = √ 4+121</h3><h3>BC = √ 125 = 11.18</h3>

to find measure of angle C use sinerule

<h3>C = 10.305</h3><h3>C = 10 (approximately)</h3>

4 0

2 years ago