Answer:
y=1/4x
Step-by-step explanation:
y=mx+b
m=1/4
so, y=1/4x+b
Now, look at our line's equation so far: . b is what we want, the 1/4 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (4,1).
So, why not plug in for x the number 4 and for y the number 1? This will allow us to solve for b for the particular line that passes through the point you gave!.
(4,1). y=mx+b or 1=1/4 × 4+b, or solving for b: b=1-(1/4)(4). b=0.
y=1/4x+0
Given:
Width of the rectangular yard = x feet
Length of the rectangular yard = x+4 feet
Perimeter of the rectangular yard is:

Perimeter of the yard = 84 feet
To find:
The length of the rectangular yard.
Solution:
Perimeter of the yard is 84 feet.



Divide both sides by 4.


So, the width of the rectangular yard is 19 feet.
Length = 
Length = 
The length of the rectangular field is 23 feet.
Therefore, the correct option is B.
Answer:
y = 2x - 1 Graph B
y = 2x + 2 Graph A
y = 2x - 5 Graph C
Step-by-step explanation:
y = mx + c
c is where the line intersect the Y axis.
<h2>Substitute x for 0:</h2>
y = 2x - 1
2 * 0 - 1 = -1.
This is graph B because it intersects at 0,-1.
y = 2x + 2
2 * 0 + 2 = 2
This is graph A because it intersects at 0,2.
y = 2x - 5
2 * 0 - 5 = -5
This is graph C because it intersects at 0,-5.
Answer:
12 m
Step-by-step explanation:
The path of a football has been modeled by the equation:

where h represents the height and d represents the horizontal distance.
When the ball lands, it means that its height is back at 0 metres. This means that we have to find horizontal distance, d, when height, h, is 0.
=> 


∴ d = 0 m
and
10d - 120 = 0
=> d = 120 / 10 = 12 m
There are two solutions for d when h = 0 m.
The first solution (d = 0 m) is a case where the ball has not been thrown at all. This means the ball has not moved away from the football player and it is still on the ground.
The second solution is the answer to our problem (d = 12 m). The ball lands at a horizontal distance of 12 m