The coordinates of the vertices of quadrilateral JKLM are J(-3,2), K(4,-1), L(2,-5) and M(-5,-2).
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Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.
To start off, you need to take the cube root of both sides of the equation.
![\sqrt[3]{x} = \frac{ \sqrt[3]{27} }{ \sqrt[n]{64} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%7D%20%3D%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B27%7D%20%7D%7B%20%5Csqrt%5Bn%5D%7B64%7D%20%7D%20)
The cube root of 27 is 3, and the cube root of 64 is 4.
The answer would then be x=3/4
The cube root of 27 is 3, and the cube root of 64 is 4.
The answer would then be x=3/4