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fredd [130]
3 years ago
13

Sally ate 1/6 of a fruit pie and gave 1/5 of the remainder to her sister. What fraction of fruit pie did she give away? hURYY

Mathematics
1 answer:
Zigmanuir [339]3 years ago
3 0

Answer:

Milan puts 1/4 of her lawn-mowing money in savings and uses 1/2 of the remaining money to pay back her sister. If she has $15 left

Step-by-step explanation:

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(83.9x10^12)(2.87x10^-3)/ 3.76x10^2
RideAnS [48]
<u>(83.9 × 10^12)(2.87 × 10^-³)</u>
             3.76 × 10²
<u>(83,900,000,000,000)(0.00287)</u>
                   376
 <u>240,793,000,000</u>                                 
           376
640,406,914.9


8 0
3 years ago
identify an equation in the point-slope form for the line parallel to y=1/2 x -7 that passes through (-3,-2)
Mariulka [41]

Answer:

Step-by-step explanation:

hello :

note :

Use the point-slope formula.

y - y_1 = m(x - x_1)   when : x_1= -3      y_1= -2         m= 1/2(parallel means same slope)

an equation in the point-slope form is : y +2 = 1/2(x+3)

3 0
3 years ago
-1\dfrac{60}{100} + 0.1 + \dfrac{1}{4} =−1 100 60 ​ +0.1+ 4 1 ​
Jlenok [28]

Answer: Your question doesn't make any sense

Step-by-step explanation:

8 0
3 years ago
In response to very high demand, a new bike has been marked up by 25% and is now selling for 210.00. how much was the bike befor
harina [27]
Call the price of the bike before mark up 'x', then we have:

x + 0.25x = 210
      1.25x = 210 
             x = 168

Therefore, the bike cost $168 before 25% price increase.


3 0
3 years ago
Read 2 more answers
In 2012 your car was worth $10,000. In 2014 your car was worth $8,800. Suppose the value of your car decreased at a constant rat
Sonbull [250]

Answer:

g(t) = 10000(0.938)^t

Step-by-step explanation:

Given data:

car worth is $10,000 in 2012

car worth is $8000 in 2014

let linear function is given as

P(t) = at + b

which denote the value of car in year t

take t =0 for year 2012

at t =0, 10,000 = 0 + b

we get b = 10,000

take t =2 for year 2014

at t =2, P(2) = 2a + b

8800 = 2a + 10,000

a = - 600

Thus the price of car at year t after 2012 is given as p(t) = -600t + 10000

let the exponential function p(t)  =ab^2 where t denote t = 0 at 2012

putting t = 0 P(0) = 10,000 we get 10,000 = ab^0

a = 10,000

putting t = 2 p = 8800

8800 =ab^2

b^2 = \frac{8800}{10000}

b = 0.938

g(t) = 10000(0.938)^t

3 0
3 years ago
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