The formula of the midpoint of HE:
We have H(0; 0) and E(2a; 2a). Substitute:
We have H(0; 0) and E(2a; 2a). Substitute:
-1\dfrac{60}{100} + 0.1 + \dfrac{1}{4} =−1 100 60 +0.1+ 4 1
1 answer:
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Step-by-step explanation:
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- ( 1 , 5 )
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- y = 2x + 3
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- Whether the point ( 1 , 5 ) , a solution to the equation y = 2x + 3 or not.
Assuming the the value of x and y as 1 and 5 respectively. Now , plug the values of x and y in the given equation & let's see whether the point ( 1 ,5 ) , solution to the equation y = 2x + 3 or not !
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Since we got 5 on R.H.S & L.H.S, So yeah! The point ( 1 , 5 ) is a solution to the equation y = 2x + 3.
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