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Bond [772]
3 years ago
12

-1\dfrac{60}{100} + 0.1 + \dfrac{1}{4} =−1 100 60 ​ +0.1+ 4 1 ​

Mathematics
1 answer:
Jlenok [28]3 years ago
8 0

Answer: Your question doesn't make any sense

Step-by-step explanation:

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Quadrilateral EFGH has coordinates E(2a, 2a), F(3a, a), G(2a, 0), and H(0, 0). Find the midpoint of he
Gre4nikov [31]
The formula of the midpoint of HE:
\left(\dfrac{x_H+x_E}{2};\ \dfrac{y_H+y_E}{2}\right)

We have H(0; 0) and E(2a; 2a). Substitute:
\left(\dfrac{0+2a}{2};\ \dfrac{0+2a}{2}\right)=(a;\ a)

4 0
3 years ago
Read 2 more answers
Approximate π + √70 to the nearest hundredth.<br><br> 8.37<br> 11.14<br> 11.51<br> 12.14
stellarik [79]

Answer:

The answer would be 11.51

Step-by-step explanation:

π is rougroughly 3.14

√70 = 8.37

3.14 + 8.37 = 11.51

8 0
1 year ago
Read 2 more answers
Convert the fraction into a decimal:<br>1/2​
mixas84 [53]
It is 0.5 because 1/2 x 1 is 0.5
7 0
3 years ago
Read 2 more answers
Please help me for the braainliest answer
Vinvika [58]

Answer:

TO find the value for the terms, substitute n for the number in the sequence. so

for 1st term n = 1

for 2nd term n =2 etc.

1st Term = 1^2-3 = 1-3 = -2

2nd term = 2^2 - 3 = 4-3 = 1

3rd Term = 3^2 - 3 = 6

10th Term = 10^2 - 3 = 100 - 3 = 97

Hope this helps

5 0
2 years ago
Is the point (1,5)a solution to the equation y=2x+3?​
Flura [38]

Step-by-step explanation:

✰ \underline{ \underline{ \large{ \tt{ G \: I \: V \: E \: N  \: \: P \: O \: I \: N \: T}}}} :

  • ( 1 , 5 )

✰ \underline{ \underline{ \large{ \tt{G \: I \: V\: E \: N \:  \: E \: Q \: U \: A \: T \: I \: O \: N}}}} :

  • y = 2x + 3

✰ \underline{ \underline{ \large{ \tt{T \: O \:  \: F\:I \: N \: D}}} }:

  • Whether the point ( 1 , 5 ) , a solution to the equation y = 2x + 3 or not.

\underline{ \underline{ \large{  \tt{S \: O \: L\: U \: T \: I \: O \: N}}}} :

Assuming the the value of x and y as 1 and 5 respectively. Now , plug the values of x and y in the given equation & let's see whether the point ( 1 ,5 ) , solution to the equation y = 2x + 3 or not !

⟶ \large{ \tt{5 = 2 \times 1 + 3}}

⟶ \large{ \tt{5 = 2 + 3}}

⟶ \large{ \tt{5 = 5}}

Since we got 5 on R.H.S & L.H.S, So yeah! The point ( 1 , 5 ) is a solution to the equation y = 2x + 3.

Hope I helped ! ♡

Have a wonderful day / night ! ツ

# \underbrace{ \tt{Carry \: On \: Learning}} !! ✎

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4 0
3 years ago
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