3 years ago

Please help with this math question (photo)

Mathematics

1 answer:

miss Akunina [59]3 years ago

6 0

If you could move the photo a little I can answer it

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Identify the following series as arithmetic, geometric, both, or neither. 3a + 3a² + 3a³ + . . . + 3an geometric arithmetic neit

kompoz [17]

Answer:

solution

given=3a+3a^2+3a^3+....+...+...3an

first term(t1)=3a

second term(t2)=3a^2

third term(t3)=3a^3

for arithmetic mean ,d1=d2

d1=t2_t1=3a^2_3a=3a(a_1)

d2=3a^3_3a^2=3a^2(a_1)

here d1 is not equal to d2.

so it's not an arithmetic series.

Again,for geometric mean,r1=r2

r1=d2/d1=3a^2/3a=a

r2=d3/d2=3a^3/3a^2=a

here ,r1 is equal to r2.

so ,it's an geometric series.

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4 years ago

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kotegsom [21]

Answer:

is there a y part of this equation?

Step-by-step explanation:

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3 years ago

Which doubles fact helps you solve 5+6=11

Rama09 [41]

I'm pretty sure it would be 5+5=10. I might be wrong. Mark me as brainliest please!

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4 years ago

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Please give me the correct answer.ACE,Moderator,Genius,and Expert please help me.

Nadusha1986 [10]

Answer:

Initial value is (0 , 24) or just y = 24

Step-by-step explanation:

Initial value of a linear function is the y intercept

y = -3x + 24

x = 0, y = 24

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3 years ago

What are the x-coordinates of the solutions to this system of equations?

Vikentia [17]

X equals 4 because 2 times 2 equals 4 and then 4 times 4 =16

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