Please help with this math question (photo)

A bowl contains blueberries and strawberries there are a total of 20 bares in the bowl the ratio blueberries to strawberries is

Alexus [3.1K]

Answer:

16 blueberries and 4 strawberries

Step-by-step explanation:

Given:

A bowl contains blueberries and strawberries there are a total of 20 berries in the bowl.

The ratio blueberries to strawberries is 4 to 1

Question asked:

How many of each berry are in the bowl ?

Solution:

Ratio of blueberries and strawberries = 4 : 1

Let ratio be $x$

Number of blueberries in the bowl = $4x$

Number of strawberries in the bowl = $1x=x$

As total berries in the bowl are 20 and the bowl contains both blueberries and strawberries in the ratio 4 : 1 :-

$4x+x=20\\5x=20\\$

Dividing both sides by 5

$x=4$

Number of strawberries in the bowl = $x$ = 4

Number of blueberries in the bowl = $4x$ = $4\times4=16$

Thus, there are 16 blueberries and 4 strawberries in the bowl.

5 0

2 years ago

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: Find the approximate perimeter of the isosceles triangle A OPD.

AleksAgata [21]

Answer:

24.98 units

Step-by-step explanation:

The picture of the question in the attached figure

we have the coordinates

P(1,-6),D(4,3),O(7,-6)

The perimeter of triangle OPD is equal to

$P=OP+PD+OD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance OP

we have

O(7,-6),P(1,-6)

substitute in the formula

$d=\sqrt{(-6+6)^{2}+(1-7)^{2}}$

$d=\sqrt{(0)^{2}+(-6)^{2}}$

$d_O_P=6\ units$

step 2

Find the distance PD

we have

P(1,-6),D(4,3)

substitute in the formula

$d=\sqrt{(3+6)^{2}+(4-1)^{2}}$

$d=\sqrt{(9)^{2}+(3)^{2}}$

$d_P_D=\sqrt{90}\ units$

step 3

Find the distance OD

we have

O(7,-6),D(4,3)

substitute in the formula

$d=\sqrt{(3+6)^{2}+(4-7)^{2}}$

$d=\sqrt{(9)^{2}+(-3)^{2}}$

$d_O_D=\sqrt{90}\ units$

step 4

Find the perimeter

$P=6+\sqrt{90}+\sqrt{90}$

$P=6+9.49+9.49=24.98\ units$

4 0

3 years ago

Please answer this question only if you know the answer!! 26 points and brainliest!

oksano4ka [1.4K]

Answer:

(4,3) is the answer

Step-by-step explanation:

4 0

3 years ago

Need help on math question thanks A) 0.303 B) 0.435 C) 0.406 D) 0.154

Airida [17]

Answer:

A) 0.303

The probability that a randomly selected student from the class has brown eyes , given they are male

$P(\frac{B}{M} ) = 0.3030$

Step-by-step explanation:

Explanation:-

Given data

Brown Blue Hazel Green

Females 13 4 6 9

Males 10 2 9 12

Let 'B' be the event of brown eyes

Total number of males n(M) = 33

Let B/M be the event of randomly selected student from the class has brown eyes given they are male

The probability that a randomly selected student from the class has brown eyes , given they are male

$P(\frac{B}{M} ) = \frac{n(B)}{n(M)}$

From table the brown eyes from males = 10

$P(\frac{B}{M} ) = \frac{10}{33}$

$P(\frac{B}{M} ) = 0.3030$

Final answer:-

The probability that a randomly selected student from the class has brown eyes , given they are male

$P(\frac{B}{M} ) = 0.3030$

8 0

3 years ago

Which number is between 5/2 and the square root of 11

Andrei [34K]

3 hoped that helped you

4 0

2 years ago

Read 2 more answers