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pashok25 [27]
3 years ago
14

Evaluate 8 - 4.7y - x when y= -1 and x= 2.

Mathematics
2 answers:
Marat540 [252]3 years ago
4 0
Substitute in the values for y and x into the equation.

so..

8 - 4.7(-1) - (2)   solve the equation 
8 + 4.7 -2 
12.7 - 2 
10.7 
ollegr [7]3 years ago
4 0
If you substitute the values in to the equation, you will get:
8 - (4.7 * -1) - 2 and that will get you to...
8 - (-4.7) - 2
8 + 4.7 - 2
= 10.7
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Question 10 of 10
docker41 [41]

Answer:

4

Step-by-step explanation:

\frac{ \sqrt{9} \times  \sqrt{144}  }{ \sqrt{81 } }  \\  \\  \frac{3 \times 12}{9}  \\  \\  \frac{36 }{9}  \\  \\  = 4

8 0
3 years ago
If two angles of a triangle have measures of 42° and 20°, what is the measure of the
iris [78.8K]

Answer:

118°

Step-by-step explanation:

the angle measures of a triangle will always add up to 180

so..

42+20=62

180-62=118

4 0
3 years ago
Read 2 more answers
Which of the following is not a property of a chi-square distribution?
laiz [17]

Answer:

c) Is not a property (hence (d) is not either)

Step-by-step explanation:

Remember that the chi square distribution with k degrees of freedom has this formula

\chi_k^2 = \matchal{N}_1^2 +  \matchal{N}_2^2 + ... + \, \matchal{N}_{k-1}^2 +  \matchal{N}_k^2

Where N₁ , N₂m .... N_k are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.

Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true

The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.

6 0
3 years ago
PLEASE HELP ASAP!! I REALLY NEED HELP!
rewona [7]
The length is 37in. The width is 7in.
8 0
3 years ago
Read 2 more answers
Factor out completly: 6x^2y − 3xy − 24xy^2 + 12y^2
Crank
<h3>I'll teach you how to factor 6x^2y − 3xy − 24xy^2 + 12y^2</h3>

---------------------------------------------------------------------

6x^2y − 3xy − 24xy^2 + 12y^2

Apply exponent rule:

6x^2y-3xy-24xyy+12yy

Rewrite 12 as 4*3

Rewrite -24 as 8*3

Rewrite 6 as 2*3

2*3x^2y-3xy+8*3xyy+4*3yy

Factor out common term 3y:

3y(2x^2-x-8xy+4y)

Factor 2x^2-x-8xy+4y:

3y(2x-1)(x-4y)

Your Answer Is 3y(2x-1)(x-4y)

plz mark me as brainliest if this helped :)

8 0
3 years ago
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