Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
x = 20°
y = 70°
Step-by-step explanation:
the angle adjacent to the 40° angle must be 140° because the two angles form a straight line (which contains 180°)
in the isosceles triangle with the 'x', that means the other two angles must be equal and are (180-140) ÷ 2, which equals 20°
to find 'y', consider the larger right triangle with angles of 90° and 20°; angle y must equal 180 - (90 + 20) = 70°
Stretched vertically three times because you take the result of x^2+4x+4 aka (x+2)^2 and then multiply it by 3 for 3 times the output
Answer: d
Step-by-step explanation:
t= b1- B0/ SE(b1) = 2.37-0/0.65= 3.646 -> 3.65
Answer:
b
Step-by-step explanation:
