Question

Y-8= - * - 4 y=-* 4 (3,-5) no solution an infinite number of solutions

Answer 1

Given:

The system of equation is

$y-8=-\dfrac{1}{3}x-4$

$y=-\dfrac{1}{3}x-4$

To find:

The solution of given system of equations.

Solution:

The slope intercept form of a line is

$y=mx+b$

Where, m is slope and b is y-intercept.

Write the given equation in slope intercept form.

The first equation is

$y-8=-\dfrac{1}{3}x-4$

$y=-\dfrac{1}{3}x-4+8$

$y=-\dfrac{1}{3}x+4$              ...(i)

Here, slope is $-\dfrac{1}{3}$ and y-intercept is 4.

The second equation is

$y=-\dfrac{1}{3}x-4$              ...(i)

Here, slope is $-\dfrac{1}{3}$ and y-intercept is -4.

Since the slopes of both lines are same but the y-intercepts are different, therefore the given equations represent parallel lines.

Parallel lines never intersect each other. So, the given system of equation has no solution.

Hence, the correct option is B.