Answer:
plz add more info
Step-by-step explanation:
in the given interval when
.
when
.
Your answer is going to be D. 3.6
The range is the greatest number in the data set subtracted by the least number in the data set.
Hope this helped!
Answer:
7 ( x + 3 )
Step-by-step explanation:
Use order of operations to multiply first.
3+2x2 +7 x + 14
3+4 +7 x + 14
Now group like terms.
3+ 7x + 4 + 14
Add like terms
7x + 21
Find the two multiples of 21.
7x + 7 x 3
Now factor out the 7.
7( x + 3 )
Answer:
the probability is P=0.012 (1.2%)
Step-by-step explanation:
for the random variable X= weight of checked-in luggage, then if X is approximately normal . then the random variable X₂ = weight of N checked-in luggage = ∑ Xi , distributes normally according to the central limit theorem.
Its expected value will be:
μ₂ = ∑ E(Xi) = N*E(Xi) = 121 seats * 68 lbs/seat = 8228 lbs
for N= 121 seats and E(Xi) = 68 lbs/person* 1 person/seat = 68 lbs/seat
the variance will be
σ₂² = ∑ σ² (Xi)= N*σ²(Xi) → σ₂ = σ *√N = 11 lbs/seat *√121 seats = 121 Lbs
then the standard random variable Z
Z= (X₂- μ₂)/σ₂ =
Zlimit= (8500 Lbs - 8228 lbs)/121 Lbs = 2.248
P(Z > 2.248) = 1- P(Z ≤ 2.248) = 1 - 0.988 = 0.012
P(Z > 2.248)= 0.012
then the probability that on a randomly selected full flight, the checked-in luggage capacity will be exceeded is P(Z > 2.248)= 0.012 (1.2%)
