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zheka24 [161]
3 years ago
9

If H is in the interior of ∠EFG, m∠EFH = 75°, and m∠HFG = (10x)°, and m∠EFG = (20x − 5)°, then x = ? and m∠HFG = ?

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

x=8

\m\angle HFG= 80^\circ

Step-by-step explanation:

Given that:

Point H is interior of \angle EFG.

m\angle EFH = 75^\circ\\m\angle HFG = (10x)^\circ\\m\angle EFG = (20x-5)^\circ

To find:

x = ?\\m\angle HFG = ?

Solution:

First of all, let us represent the given values in the form of a diagram.

Kindly refer to the attached image for the given points and values of angles.

We can clearly see that:

m\angle EFG = m\angle EFH + m\angle HFG

Putting all the values given in above equation, we get:

(20x-5)^\circ = 75^\circ + 10x^\circ\\\Rightarrow 20x-10x=75+5\\\Rightarrow 10x =80\\\Rightarrow \bold{x =8}

m\angle HFG =10x^\circ\\\Rightarrow m\angle HFG =10\times 8^\circ\\\Rightarrow m\angle HFG = \bold{80^\circ}

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PLEASE HELP! THANKS!!
stepladder [879]
X=12 because I said so and I’m smart
7 0
3 years ago
Which is a solution for 3 > f? f = 7 f = 9 f= 3 f =2?
Fed [463]

Answer:

F = 2

Step-by-step explanation: If you want to know which one is a solution, you have to substitute the numbers in for F.

F = 7:

3 > f

3 > 7

This is false because 3 is NOT greater than 7, it is less than 7.

F = 9:

3 > f

3 > 9

This is false because 3 is NOT greater than 9, it is less than 9.

F = 2:

3 > f

3 > 2

This is TRUE because 3 IS greater than 2.


Hope this help you!!! :)




4 0
3 years ago
Jenny uses a roller to paint a wall. The roller has a radius of 1.75 inches and a height of 10 inches. In two rolls, what is the
Katen [24]

Answer:

The area of the wall that she will paint in two rolls is <u>219.8 inches²</u>.

Step-by-step explanation:

Given:

Jenny uses a roller to paint a wall. The roller has a radius of 1.75 inches and a height of 10 inches.

Now, to find the area of the wall that she will paint in two rolls.

So, we find the lateral surface area of roller.

Radius (r) = 1.75 inches.

Height (h) = 10 inches.

So, to get the lateral surface area we put formula:

A_{L} =2\pi rh

A_L=2\times 3.14\times 1.75\times 10

A_L=109.9\ inches^2.

Thus, the lateral surface area of the roller = 109.9 inches².

Now, to get the area of wall that she will paint in two rolls we multiply 2 by the lateral surface area of the roller:

109.9\times 2\\\\=219.8\ inches^2.

Therefore, the area of the wall that she will paint in two rolls is 219.8 inches².

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