D or the last dot how ever you wanna describe it
Answer:
The value of the test statistic and degrees of freedom is 2.148 and 11 respectively.
Step-by-step explanation:
Consider the provided information.
The mean annual tuition and fees for a sample of 12 private colleges was 36,800 with a standard deviation of 5,000 .
Thus, n = 12, σ = 5000
degrees of freedom = n-1 = 12-1 = 11
Formula to find the value of z is:
Where is mean of sample, μ is the mean of population, σ is the standard deviation of population and n is number of observations.
Hence, the value of the test statistic and degrees of freedom is 2.148 and 11 respectively.
5p + 30 = 12p <== ur equation
5p - 12p = -30
-7p = -30
p = -30/-7
p = 4 2/7 pies to break even