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telo118 [61]
2 years ago
7

The principal at valley elementary school had 840 stickers that he gave to 42 children. 2/3 of the children were boys and each o

f them received the same number of stickers. Each girl received twice as many as each boy. How many stickers did each girl received
Mathematics
1 answer:
STatiana [176]2 years ago
4 0

Answer: each girl received 30 stickers.

Step-by-step explanation:

Let x represent the number of stickers that the boys received.

Let y represent the number of stickers that the girls received.

The total number of children was 42. 2/3 of the children were boys. It means that the number of boys were

2/3 × 42 = 28

The number if girls would be

42 - 28 = 14

The total number of stickers that the school principal shared was 840. It means that

28x + 14y = 840- - - - - - - - -1

Each of the boys received the same number of stickers while each girl received twice as many as each boy. It means that

y = 2x

Substituting y = 2x into equation 1, it becomes

28x + 14 × 2x = 840

28x + 28x = 840

56x = 840

x = 840/56

x = 15

y = 2x = 15 × 2

y = 30

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The description below represents Function A and the table represents Function B: Function A The function is 2 more than 5 times
Vlad [161]

Answer:

The slope of Function A is greater than the slope of function B  while the y-intercept of Function  B is greater than the y-intercept of function A.

Step-by-step explanation:

Function A is f(x) = 5x + 2

The slope is 5 and the y-intercept is (0, 2).

Function B. The slope is  (5-2) / (0- -1) = 3.

also (8-5) / (1 - 0) = 3

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7 0
2 years ago
Plz help me and answer right
azamat
I think it might be 30 but I don’t know
3 0
2 years ago
Read 2 more answers
The expression (x − 4)2 is equivalent to x2 − 16 x2 + 16 x2 − 8x + 16 x2 + 8x + 16
zzz [600]

Answer:

Given below

Step-by-step explanation:

The algebraic identity is (a-b)^2

= a^2 + b^2 - 2ab

So it'll be,

(x-4)^2

= x^2 + (4)^2 - (2)(x)(4)

= x^2 -8x + 16

or x^2 +16 -8x

4 0
2 years ago
Ayúdenme en este ejercicio por favor
lapo4ka [179]

Para poder encontrar el número total de conjuntos de diferentes números, lo primero que debemos contar es el número de opciones para cada una de las selecciones.

A) Para el primer número tenemos 47 opciones

para el segundo número tenemos 46 opciones, pues una ya fue seleccionada.

Para el tercer número tenemos 45 opciones

Para el cuarto número tenemos 44 opciones

Para el quinto número tenemos 43 opciones

Para el sexto número, el mega número, tenemos 27 opciones.

El número total de combinaciones es igual al producto entre los numeros de opciones:

C = 47×46×45×44×43×27 = 4,969,962,360

B) Ahora sabemos que dos de los primeros 5 números tienen valores fijos A y B.

Asumamos que son el primero y segundo número.

Entonces:

El primer número es A (1 opcion)

El segundo número es B (1 opcion)

El tercer número tiene 45 opciones (por que dos ya fueron seleccionadas)

El cuarto número tiene 44 opciones

El quinto número tiene 43 opciones

El sexto número tiene 27 opciones.

Para encontrar el número total de combinaciones no solamente deberemos multiplicar los números de opciones, tambien tendremos que tener en cuenta el número de permutaciones de 2 elementos (A y B) entre los primeros 5 posibles espacios.

Para calcular esto vemos cuantas posibles opciones tiene cada uno de ellos.

El número A tiene 5 posibles posiciones (5 opciones)

El número B tiene 4 posibles posiciones (pues una esta ocupada por A)

asú, el número de permutaciones es:

P = 5*4 = 20

Asi, en este caso el número total de combinaciones es:

C = (1×1×45×44×43×27)×20 = 45,975,600

Si quieres aprender más, puedes leer:

brainly.com/question/21591279

7 0
2 years ago
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