Answer:
The probability of a customer buying carrots is 0.10.
Step-by-step explanation:
Here, given:
P (Customer buying apples) = 12%
⇒ P(A) = 12 \100 = 0.12
P(Customer Buying apples AND Carrots) = 5%
⇒ P(A ∩ C ) = 5 /100 = 0.05
P(Customer buying apples OR carrots ) = 17%
⇒ P(A∪ C) = 17/100 = 0.17
Now, we know that:
<h3>
P(X ∪ Y) = P(X) + P(Y) - P(X ∩ Y ) </h3><h3>
</h3>
Now, here substituting the values, we get:
P(A∪ C) = P(A) + P(C) - P(A ∩ C )
⇒ 0. 17 = 0.12 + P(C) - 0.05
or, 0.17 - 0.07 = P(C)
or, P(C) = 0.10
or, P(Customer Buying Carrots) = 0.10
Hence, the probability of a customer buying carrots is 0.10.
\left[x \right] = \left[ \frac{-1}{4}\right][x]=[4−1] = x*3 +3x*2+6) - (9x*2-5x+7
Answer:
Bonita's product is too large
Step-by-step explanation:
The two factors in the problem are (5/6) and (5/3). The factor 5/6 is less than 1, ensuring that the product will be less than 5/3.
Bonita's result of 7/3 is more than 5/3, so is too large to be the product.
Answer:
a.
Step-by-step Explanation:
Given:
Distance Ottawa to Québec = 425 km
Initial flight rate = v + 60
Return flight rate = v - 40
Required:
Flight times difference of the initial and return flights
Solution:
=>Flight time of the initial flight:
=>Flight time of the return flight:
=>Difference in flight times: