Answer:
25 ft^2
Step-by-step explanation:
In direct variation, if y varies directly with x, then the equation has the form
y = kx,
where k is the constant of proportionality. y is proportional to x.
Let's call the area y and the distance x.
Here, the area varies with the square of the distance, so the equation has the form
y = kx^2
Here, y is proportional to the square of x.
We can find the value of k by using the given information.
y = kx^2
When x = 20 ft, y = 16 ft^2.
16 = k(20^2)
k = 16/400
k = 1/25
The equation of the relation is:
y = (1/25)x^2
Now we use the equation we found to answer the question.
What is y (the area) when x (the distance) is 25 ft?
y = (1/25)x^2
y = (1/25)(25^2)
y = 25
Answer: 25 ft^2
Answer:
Step-by-step explanation:
Hi there!
![\large\boxed{f^{-1}(x) = \sqrt[3]{\frac{x+4}{9} } }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7Bf%5E%7B-1%7D%28x%29%20%3D%20%20%5Csqrt%5B3%5D%7B%5Cfrac%7Bx%2B4%7D%7B9%7D%20%7D%20%7D)
Find the inverse by replacing f(x) with y and swapping the x and y variables:
Isolate y by adding 4 to both sides:
Divide both sides by 9:
Take the cube root of both sides:
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The data distribution is positively skewed
