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beks73 [17]
3 years ago
6

Bill baked 16 cookies with 2 scoops of flour. With 4 scoops of flour, how many cookies can Bill bake? Assume the relationship is

directly proportional.
Mathematics
2 answers:
iogann1982 [59]3 years ago
7 0

Answer:

Let c = the number of cookies

cookies/scoops of flour: 12/2 = c/3

Cross multiply.

2c = 36

c = 18 cookies

Step-by-step explanation:

madreJ [45]3 years ago
6 0

Answer:

32 cookies.

Step-by-step explanation:

Find how much cookies Bill can bake with just 1 scoop of flour:

2 scoops of flour = 16 cookies

1 scoop of flour = 16 ÷ 2 = 8 cookies

Now, find 4 scoops of flour.

4 scoops of flour = 8 x 4 = 32 cookies

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Answer:

see below

Step-by-step explanation:

2x+8y=12 3x-8y=11

If we have to solve by substitution, Take the first equation and divide by 2

2x/2 + 8y/2 =12/2

x+4y = 6

Then subtract 4y from each side

x = 6 -4y

Then substitute this into the second equation

This is best solved by elimination

2x+8y=12

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How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x​
Fofino [41]

Answer:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

Step-by-step explanation:

We are given the function:

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And we want to finds its zeros.

Therefore:

0=-4x^5-8x^3+12x

Firstly, we can divide everything by -4:

0=x^5+2x^3-3x

Factor out an x:

0=x(x^4+2x^2-3)

This is in quadratic form. For simplicity, we can let:

u=x^2

Then by substitution:

0=x(u^2+2u-3)

Factor:

0=x(u+3)(u-1)

Substitute back:

0=x(x^2+3)(x^2-1)

By the Zero Product Property:

x=0\text{ and } x^2+3=0\text{ and } x^2-1=0

Solving for each case:

x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}

Therefore, our real and complex zeros are:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

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Step-by-step explanation:

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mrs_skeptik [129]

Answer:

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Step-by-step explanation:

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