There is nothing here. If they are both equilateral triangle‘s then I would say yes
Answer:
Therefore the car takes 2 s to reach a minimum height from the ground before rising again.
Step-by-step explanation:
Given that a roller coaster ride reach a height of 80 feet.
The height above the ground of the roller coaster is modeled by the function
h(t)=10t²-40t+80
where t is measured in second.
h(t)=10t²-40t+80
Differentiating with respect to t
h'(t)= 10(2t)-40
⇒h'(t)=20t-40
To find the minimum height we set h'(t)=0
∴20t-40=0
⇒20t =40
⇒t=2
The height of the roller coaster minimum when t=2 s.
The minimum height of of the roller coaster is
h(2)= 10(2)²-40.2+80
=40-80+80
=40 feet.
Therefore the car takes 2 s to reach a minimum height from the ground before rising again.
Answer:
3, 5, 7
Step-by-step explanation:
1st number: (2k+1)
2nd number: (2k+3)
3rd number: (2k+5), k∈Z
3*[(2k+1) + (2k+3)] = 3 + 3*(2k+5)
3*(4k+4)=3+6k+15
12k+12=18+6k
6k=6
k=1
1st number: (2k+1) = 3
2nd number: (2k+3)=5
3rd number: (2k+5)=7
Answer:
90
Step-by-step explanation:
First, we should find the area of the trapezoid, and then subtract the area of the removed triangle in order to find the shaded area.
Area of the trapezoid
1) Area of the rectangle in the middle.
Base Length: 10
Height Length: 10
Area: 10 x 10 = 100
2. Area of the triangles on the side
Base Length: (14 - 10)/2 = 2
Height Length: 10
Area: 2 x 10 x 1/2 = 10
There are two triangles: 10 x 2 = 20
Area of the trapazoid: 100 + 20 = 120
Area of the triangle that's been removed
Base Length: 10
Height Length: 10 - 4 = 6
Area: 10 x 6 x 1/2 = 30
Shaded area
Area of the trapezoid - Area of the triangle
120 - 30 = 90
Area of the shaded region is 90.
