The area of a certain rectangle is 288 yd2. The perimeter is 68 yd. What are the dimensions of the rectangle?
1 answer:
Answer:
The rectangle is 16*18
Step-by-step explanation:
The area of a rectangle is length * width and the perimeter is 2 times length * width
A = l*w
P = 2(l+w)
Replacing A and P
288 = l*w
68 = 2(l+w) => 34 = l+w => 34 - w = l
replacing l in the area
288 = (34 - w) w
w^2 - 34w + 288 = 0
(w - 16)(w - 18)
w = 16
w = 18
replacing in 34 - w = l
you get that when w = 16, l = 18 and when w = 18, l = 16
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