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4 years ago

The area of a certain rectangle is 288 yd2. The perimeter is 68 yd. What are the dimensions of the rectangle?

Mathematics

1 answer:

arsen [322]4 years ago

8 0

Answer:

The rectangle is 16*18

Step-by-step explanation:

The area of a rectangle is length * width and the perimeter is 2 times length * width

A = l*w

P = 2(l+w)

Replacing A and P

288 = l*w

68 = 2(l+w) => 34 = l+w => 34 - w = l

replacing l in the area

288 = (34 - w) w

w^2 - 34w + 288 = 0

(w - 16)(w - 18)

w = 16

w = 18

replacing in 34 - w = l

you get that when w = 16, l = 18 and when w = 18, l = 16

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3 years ago

How many solutions exist for the given equation? StartFraction one-half left-parenthesis x plus 12 right-parenthesis equals 4 x

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Answer:

One solution x = 2

Step-by-step explanation:

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Use distributive property:

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3 years ago

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spayn [35]

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ASAP GUYS PLEASE I NEED UR HELP THIS IS SO HARD<br> Solve: 5 − 7 ( z + 1 ) = 7 ( − 9 − 3 z )

pantera1 [17]

Answer:

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Step-by-step explanation:

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We multiply the number in front of the bracket first, since that is multiplication.

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Now, we move all the z and all the numbers to each side.

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