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Yakvenalex [24]
2 years ago
5

3a≥ -6 solve for a PLEASE

Mathematics
1 answer:
ddd [48]2 years ago
5 0

Answer: Divide each term in 3 a ≥ − 6 by 3 . 3 a 3 ≥ − 6 3 Cancel the common factor of 3 . Tap for more steps... a ≥ − 6 3 Divide − 6 by 3 . a ≥ − 2 The result can be shown in multiple forms. Inequality Form: a ≥ − 2 Interval Notation: [ − 2 , ∞ )

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Convert y + 1 = 3/4 (x - 16) to standard form.
Archy [21]
3x/4-y=13 or choice B
7 0
3 years ago
#10. Would I do 3length•1width•2height?
sergeinik [125]
Yes, you are right. the length is 3, the height is 2, and the width is 1

5 0
3 years ago
Read 2 more answers
Suppose given △ABD and △CBD.
patriot [66]

Answer:

The required result is proved with the help of angle bisector theorem.

Step-by-step explanation:

Given △ABD and △CBD, AE and CE are the angle bisectors. we have to prove that \frac{AD}{AB}=\frac{DC}{CB}

Angle bisector theorem states that an angle bisector of an angle of a Δ divides the opposite side in two segments that are proportional to the other two sides of triangle.

In ΔADB, AE is the angle bisector

∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment AD to the line segment AB.

\frac{DE}{EB}=\frac{AD}{AB}   →  (1)

In ΔDCB, CE is the angle bisector

∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment CD to the line segment CB.

\frac{DE}{EB}=\frac{CD}{CB}    →  (2)

From equation (1) and (2), we get

\frac{AD}{AB}=\frac{CD}{CB}

Hence Proved.

5 0
3 years ago
How do you solve the system 3x-y z=5, x 3y 3z=-6, and x 4y-2x=12?
dlinn [17]
3x - y + z = 5 . . . (1)
x + 3y + 3z = -6 . . . (2)
x + 4y - 2z = 12 . . . (3)

From (2), x = -6 - 3y - 3z . . . (4)
Substituting for x in (1) and (3) gives
3(-6 - 3y - 3z) - y + z = 5 => -18 - 9y - 9z - y + z = 5 => -10y - 8z = 23 . .  (5)
-6 - 3y - 3z + 4y - 2z = 12 => y - 5z = 18 . . . (6)

(6) x 10 => 10y - 50z = 180 . . . (7)
(5) + (7) => -58z = 203
z = 203/-58 = -3.5

From (6), y - 5(-3.5) = 18 => y = 18 - 17.5 = 0.5
From (4), x = -6 - 3(0.5) - 3(-3.5) = -6 - 1.5 + 10.5 = 3

x = 3, y = 0.5, z = -3.5
8 0
3 years ago
PLS HELP ASAP If -2 is added to each of the x and y intercepts of the line 3x + 2y = 6, find the new equation of the line
ella [17]

Answer:

3x + 2y = -4

Step-by-step explanation:

x intercept of the line occurs at y = 0

Given the equation 3x+2y = 6

3x+2(0) = 6

3x  = 6

x = 2

The x intercept is at (2, 0)

Adding -2 to each axis will give (2-2, 0-2) = (0, -2)

y intercept of the line occurs at x = 0

Given the equation 3x+2y = 6

3(0)+2y = 6

2y  = 6

y =3

The x intercept is at (0, 3)

Adding -2 to each axis will give (0-2, 3-2) = (-2, 1)

The new coordinates are (0, -2 and (-2, 1)

Using the point slope form of the equation y - y0 = m(x-x0)

slope m = y2-y1/x2-x1

m = 1-(-2)/-2-0

m = 1+2/-2

m = -3/2

Using m = -3/2 and (0, -2)

y - (-2) = -3/2(x-0)

y+2 = -3/2 x

2(y+2) = -3x

2y+4 = -3x

-3x-2y = 4

3x + 2y = -4

Hence the required equation is 3x + 2y = -4

7 0
2 years ago
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