2014⇒2277 athletes
2013⇒2070 athletes.
x=number of athletes in 2013
110% of x=2277
(110/100x=2277
x=(2277*100)/110=2070
2012⇒2300 athletes.
x=number of athletes in 2012
90% of x=2070
(90/100)x=2070
x=(2070*100)/90=2300
Answer: 2300 athletes were signed up for a spring sport in 2012.
You just need to plug those expressions inside the formula: it doesn't matter if they're expressions involving a variable instead of plain numbers: the formula becomes
If you want, you can simplify it by expanding the square and then multiply the two parenthesis:
A) The longest horizontal distance is reached at 45 degrees angle. This is true for any projectile launch.
B) First, calculate fligth time (using the vertical motion) and then calculate the horizontal movement.
Flight time = 2* ascendent time
ascendent time => final vertical velocity, Vy, = 0
sin(45) = Voy / Vo => Voy = Vosin(45) = 25.5 m/s * (√2) / 2 = 18.03 m/s
Vy = Voy - gt = 0 => Voy = gt = t = Voy / g
Use g = 10 m/s^ (it is an aproximation, because the actual value is about 9.81 m/s^2 depending on the latitud)
t = 18.03 m/s / 10 m/s^2 = 1.83 s
This is the ascendant time going upward.
The flight time is 2*1.83 = 3.66 s
Horizontal motion
Horizontal velocity = Vx = constant = Vox = Vo*cos(45) = 18.03 m/s
Vx = x / t => x = Vx*t
Horizontal distance = xmax = 18.03m/s*3.66 s = 65.99 m
c) The time the ballon will be in the air was calculated in the part B, it is 18.03 s
First we need to find where the 2 graphs intercept.
x^2 + 3 = - (x^2 - 4x + 4) + 7
x^2 + 3 = -x^2 + 4x + 3
2x^2 - 4x = 0
2x(x - 2)
x = 0 , 2. are x coordinates of the 2 intercepts.
Answer: a) H = h( 0.5 )^n
b) H = 1.125inches
Step-by-step explanation:
Let H = height of the ball
n = number of time the ball bounces
h = initial height.
The exponential function to model the height of the ball will be:
H = h( 1 - 0.5)^n
H = h( 0.5 )^n
It's minus because the height of the ball is decreasing.
h = 36 inches
n = 5
H = 36( 1 - 0.5 ) ^5
H = 36( 0.5 )^5
H = 36 × 0.03125
H = 1.125inches
