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astraxan [27]
3 years ago
10

If the number of CD's sold by Daniel's Discs on Day 7 was 25, how would the standard deviation compare to that of the original s

ix days? Explain in complete sentences why the standard deviation would be higher or lower. Complete your work in the space provided or upload a file that can display math symbols if your work requires it. Day Day 1 Day 2 Day 3 Day 4 Day 5 Day 6 CD's 15 10 10 10 18 15
Mathematics
1 answer:
bekas [8.4K]3 years ago
6 0
Damiel sold 12 more cds on the 7th day than the average over the first 6 days. to show work find the mean(average) of the 6 numbers. and subyract that from 25.
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Please answer ASAP ❤️Will earn 15 points (hope your answers are valid )
svetoff [14.1K]

Answer:  The cost of one rose bush is $7 and the cost of one shrub is also $7

Step-by-step explanation:

The situtation can be represented by the systems of the equations.

10x + 4y  =  98   x in this case is the cost of  one rose bushes

9x + 9y =  126     y  is the cost of one shrub.  

Solve the system of equation using the elimination method.

10x +4y = 98

9x + 9y = 126     eliminate the y variable so you will have to multiply 9 on top                                          and -4 down.

9(10x +4) = (98)(9)

-4(9x + 9y) = 126(-4)

You will now have the new two systems of equations

90x +36y = 882

-36x +-36y = -504    Now add the equations

0  + 54x = 378      

        54x = 378

  x= 7

Now we know that the cost of one rose bush is 7 so we will plot it into one of the equations and solve for the cost of one shrub.

90(7) +36y=882

630 +36y = 882

-630            -630

    36y = 252

   y = 7

Check:  10(7) + 4(7)= 98

              70  + 28 = 98

             98= 98  

so one rose bush is actually 7 dollars the same as 1 shrub.

5 0
2 years ago
A group of 30 bikers went on a trip. some rode bicycles and the others rode tandems. if the total number of bicycles and tandems
Marina CMI [18]
10 Tandems or 63 Tandems
5 0
3 years ago
Read 2 more answers
Given f(x) = 4x^4 find f^-1(x) Then state whether f^-1(x) is a function.
sdas [7]

Answer:

  • f^{-1}(x)=\pm\sqrt[4]{\dfrac{x}{4}}
  • f^{-1}(x) \quad\text{is not a function}

Step-by-step explanation:

To find the inverse function, solve for y:

x=f(y)\\\\x=4y^4\\\\\dfrac{x}{4}=y^4\\\\\pm\sqrt[4]{\dfrac{x}{4}}=y\\\\f^{-1}(x)=\pm\sqrt[4]{\dfrac{x}{4}}

f(x) is an even function, so f(-x) = f(x). Then the inverse relation is double-valued: for any given y, there can be either of two x-values that will give that result.

___

A function is single-valued. That means any given domain value maps to exactly one range value. The test of this is the "vertical line test." If a vertical line intersects the graph in more than one point, then that x-value maps to more than one y-value.

The horizontal line test is similar. It is used to determine whether a function has an inverse function. If a horizontal line intersects the graph in more than one place, the inverse relation is not a function.

__

Since the inverse relation for the given f(x) maps every x to two y-values, it is not a function. You can also tell this by the fact that f(x) is an even function, so does not pass the horizontal line test. When f(x) doesn't pass the horizontal line test, f^-1(x) cannot pass the vertical line test.

_____

The attached graph shows the inverse relation (called f₁(x)). It also shows a vertical line intersecting that graph in more than one place.

5 0
2 years ago
Plzzzzzzzzz help me whoever gets it right gets brainliest! how many potatoes and how many corrots
DochEvi [55]
The answer is 10 carrots and 5 potatoes.
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B80%7D%20" id="TexFormula1" title=" \sqrt[3]{80} " alt=" \sqrt[3]{80} " ali
Marianna [84]

Start by decomposing the number inside the root into primes

Then group the terms into cubes if possible

\begin{gathered} 80=2\cdot2\cdot2\cdot2\cdot5 \\ 80=2^3\cdot2\cdot5 \\ 80=10\cdot2^3 \end{gathered}

rewrite the root

\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}

then cancel the terms that are cubes and bring them out of the root

\sqrt[3]{80}=2\sqrt[3]{10}

7 0
1 year ago
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