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love history [14]
3 years ago
11

NEED HELP ASAP!!! WIL GET BRAINLIST

Mathematics
1 answer:
Norma-Jean [14]3 years ago
6 0

Answer:

1) x = 45

2) x = 61

3) x = 21

4) x = 7

5) x = 40

6) x = 9

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X-y&lt;3<br> How I can solve this inequality?
Reil [10]
X-y<3
-x -x
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-y<-x+3
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The answer is y>x-3
4 0
3 years ago
Please help nobody is helping me PLEASE
AnnZ [28]

Answer:

8 ft. tall

Step-by-step explanation:

the measurement of the height of the 10 and then judging by the height of the middle half is 8 ft.

8 0
3 years ago
PLEASE ANSWER QUICK! I REALLY NEED HELP!
Katarina [22]

Answer:

a) Angle 1 = Value in degree = 95°

b)Angle 2 = Value in degree = 77°

c) Angle 3 = Value in degree = 85°

d) Angle 4 = Value in degree = 103°

Step-by-step explanation:

We use circle theorems to solve for this above question.

a) Angle 1 = Value in degree = 95°

Inscribed Angle is 1/2 of an Intercepted Arc

From the diagram, Angle 1 intersects at Arc B and Arc C

This means Angle 1 = (B + C)/ 2 =

Arc B = 100°

Arc C = 90°

Angle 1. = (100° + 90°)/ 2 = 190/ 2 = 95°

b)Angle 2 = Value in degree = 77°

From the diagram, Angle 2 intersects at Arc C and Arc D

Inscribed Angle is 1/2 of an Intercepted Arc

This means Angle 1 = (C+ D)/ 2

C = 90°

D = 64°

Angle 1. = (90° + 64°)/ 2 = 154/ 2 = 77°

c) Angle 3 = Value in degree = 85°

From the diagram, we can see that Angle 1 is opposite Angle 3, hence,

Opposite angles are supplementary which means their addition = 180°

Mathematically:.Angle 1 + Angle 3 = 180°

Angle 1 = 95°

95° + Angle 3 = 180°

Angle 3 = 180° - 95° = 85°

d) Angle 4 = Value in degree = 103°

From the diagram, we can see that Angle 2 is opposite Angle 4,

Hence,

Opposite angles are supplementary which means their addition = 180°

Mathematically:.Angle 2 + Angle 4 = 180°

Angle 2 = 77°

77° + Angle 3 = 180°

Angle 4 = 180° - 77° = 103°

4 0
3 years ago
A water tank is box shaped with a square base of side length 5 ft. The tank is fed by a pipe above and drains from its base. In
adell [148]

Answer:

dy/dt = - (1/5) ft/s = - 0.2 ft/s

Step-by-step explanation:

Given

L = 5 ft

Qin = 25 ft³/s

Qout = 30 ft³/s

h = 10 ft

dy/dt = ?

We can apply the relation

ΔQ = Qint - Qout = 25 ft³/s - 30 ft³/s

⇒ ΔQ = - 5 ft³/s

Then we use the formula

Q = v*A

where Q = ΔQ, A = L²  is the area of square base and v = dy/dt  is the rate of change in the depth of the solution in the tank

⇒ ΔQ = (dy/dt)*L²

⇒ dy/dt = ΔQ/L²

⇒ dy/dt = (- 5 ft³/s)/(5 ft)²

⇒ dy/dt = - (1/5) ft/s = - 0.2 ft/s

6 0
3 years ago
What is the DISTANCE<br> FORMULA?
VladimirAG [237]
D= (x2-x1)^2 + (y2-y1)^2
8 0
3 years ago
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