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JulijaS [17]
3 years ago
12

Simplify the expression 2³ × 2² A. 4⁵ B. 2⁶ C. 4⁶ D. 2⁵

Mathematics
2 answers:
FrozenT [24]3 years ago
5 0

Answer: 2^{5}

Explanation: I have written this problem on the whiteboard.

For the problem on the board, since our two powers have like bases of 2, we can multiply them together by simply adding their exponents.

So 2³ · 2² is just 2^{5}.

A common mistake in this problem would

be for students to say that  2³ · 2² is 4^{5}.

It's important to understand however that when applying your

exponent rules, your base in this case 2 will not change.

mixer [17]3 years ago
3 0

Answer:

2^5

Step-by-step explanation:

The base is the same

2^3 * 2^2

We are multiplying, so we can add the exponents

2^3 * 2^2 = 2^(3+2) = 2^5

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\text{If is}\\\\\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2\end{array}

Answer:

\large\boxed{\left(-\dfrac{344}{69},\ -\dfrac{38}{3}\right)}

Step-by-step explanation:

\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2&\text{multiply both sides by (-0.3)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}0.2-0.3y=4\\-0.69x+0.3y=-0.36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-0.69x+0.2=3.64\qquad\text{subtract 0.2 from both sides}\\.\qquad-0.69x=3.44\qquad\text{divide both sides by (-0.69)}\\.\qquad x=-\dfrac{3.44\cdot100}{0.69\cdot100}\\.\qquad \boxed{x=-\dfrac{344}{69}}\\\\\text{Calculate the value of y from first equation:}

0.2-0.3y=4\qquad\text{subtract 0.2 from both sides}\\-0.3y=3.8\qquad\text{divide both sides by (-0.3)}\\y=-\dfrac{3.8\cdot10}{0.3\cdot10}\\\boxed{y=-\dfrac{38}{3}}

--------------------------------------------------------------------------

\text{If is}\\\\\left\{\begin{array}{ccc}0,2x-0,3y=4\\2.3x-y=1.2\end{array}\right

Answer:

\large\boxed{\left(-\dfrac{52}{7},\ -\dfrac{128}{7}\right)}

Step-by-step explanation:

\left\{\begin{array}{ccc}0.2x-0.3y=4&\text{multiply both sides by 10}\\2.3x-y=1.2&\text{multiply both sides by 10}\end{array}\right\\\\\left\{\begin{array}{ccc}2x-3y=40&\text{multiply both sides by (-10)}\\23x-10y=12&\text{multiply both sides by 3}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-20x+30y=-400\\69x-30y=36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad49x=-364\qquad\text{divide both sides by 49}\\x=-\dfrac{364:7}{49:7}\\.\qquad\boxed{x=-\dfrac{52}{7}}

2\left(-\dfrac{52}{7}\right)-3y=40\\-\dfrac{104}{7}-3y=40\qquad\text{multiply both sides by 7}\\-104-21y=280\qquad\text{add 104 to both sides}\\-21y=384\qquad\text{divide both sides by (-21)}\\y=-\dfrac{384:3}{21:3}\\\boxed{y=-\dfrac{128}{7}}

7 0
4 years ago
If the length of a rectangular playground is represented by the expression 2x - 3, and the width is represented by 5x + 9, what
Nimfa-mama [501]

Answer:

The expression for area of rectangle in standard form is: 10x^2+3x-27

Step-by-step explanation:

The area of rectangle is given by:

Area = Length * Width

Here, in the question, we are given length and width of the rectangle

Length = 2x-3

Width = 5x+9

The area of the rectangle will be:

Area = (2x-3)(5x+9)\\= 2x(5x+9)-3(5x+9)\\= 10x^2+18x-15x-27\\= 10x^2+3x-27

Hence,

The expression for area of rectangle in standard form is: 10x^2+3x-27

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Step-by-step explanation:

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