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Paul [167]
3 years ago
11

Kalyan's present age is one third his mothers present age . If the mothers age was 5 times his age 6 years ago ,what are their p

resent age
Mathematics
1 answer:
likoan [24]3 years ago
8 0

<u>Current ages:</u>

Let Kaylan's present age be x years

Since his age is a third of his mother's present age:

mother's age * (1/3) = Kaylan's age

mother's age * (1/3) = x        

mother's age = 3x                                     [multiplying both sides by 3]

Kaylan's mother's age would be 3x years

<u>Their ages 6 years ago: </u>

Kaylan's age: x-6 years

Mother's age: 3x-6 years

We are told that mother's age was 5 times Kaylan's age, 6 years ago. So,

5*(Kaylan's age 6 years ago) = (Mother's age 6 years ago)

<em>replacing the values</em>

5(x - 6) = 3x-6

5x - 30 = 3x-6

2x - 30 = -6                                             [subtracting 3x from both sides]

2x = 24                                                    [adding 30 on both sides]

x = 12                                                       [dividing both sides by 2]

Hence, x = 12

Kaylan's present age(x) = 12 years

Mother's present age(3x) = 3*12 = 36 years

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