A two-factor between-subjects design is evaluated. The F-value for Factor A has df = 1, 40 and the F-value for Factor B has df =
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The area of the circle is given by:
= πr²
= area, r = radius
One piece of the wire is used to form the circumference of the circle. The circumference of the circle is given by:
C = 2πr
C = circumference, r = radius
The other piece of the wire is used to form the perimeter of the square. To find the length of this piece, simply subtract C from the total length of wire, 40m:
40 - 2πr
The perimeter of the square is 4 times the length of one of its sides:
P = 4s
P = perimeter, s = side length
We know the perimeter is the length of the second piece of wire 40 - 2πr:
40 - 2πr = 4s
s = 10-πr/2
The area of the square is given by:
= s², where s = side length
s = 10-πr/2, so plug in s and solve for :
= (10-πr/2)²
Now that we have the areas of the circle and the square, let's add them up to find the total area:
+
= πr² + (10-πr/2)²