n = int(input("How many numbers do you need to check? "))
even = 0
odd = 0
for x in range(n):
num = int(input("Enter number: "))
if num % 2 == 0:
even += 1
print(str(num) + " is an even number.")
else:
odd += 1
print(str(num) + " is an odd number.")
print("You entered " + str(even) + " even number(s).")
print("You entered " + str(odd) + " odd number(s).")
This works for me. Best of luck.
A compiler is often used when you want to test your code; that would often be your second step.
<h2>A <u>Rogue attack</u> utilizes software just to attempt hundreds of frequent phrases in a row.</h2>
- Rogue access equipment would be any WLAN radio channel that isn't even authorized to communicate or join the corporate connection.
- Whenever they have been misconfigured as well as set up without authentication, it creates a new security vulnerability potentially gaining simple access to a private network.
Thus the response above is correct.
Learn more about software attacks here:
brainly.com/question/25407509
Apple first released the first ipod in 2001
