A heterogeneous ore mixture contains 35.0 % In2O3 by mass. How many tons of the ore must be mined to provide 325.0 kg of indium
metal? (2000 lb = 1 ton, assume exact)
1 answer:
Answer:
1.2375 ton of ore
Explanation:
Mass of indium = 325
Formula = In2O3
Molar mass = 277.64 g/mol
Molar mass of indium = (2*114.8)g
229.6 indium is in 277.64 of In2O3
Mass of In2O3 required = 277.64/229.6 x 325
= 392.94kg
35 % In2O3 in ore
For 35 kg = 100 kg required
For 392.94,
100/35 x 392.94
= 1122.686 kg
1122.68 x 2.2
= 2469.9 pounds
2469.9/200
= 1.235 tons of ore
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