Answer:
M of HI = 5.4 M.
Explanation:
- We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.
<em>(XMV) acid = (XMV) base.</em>
where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.
M is the molarity of the acid or base.
V is the volume of the acid or base.
<em>(XMV) HI = (XMV) Ca(OH)₂.</em>
For HI; X = 1, M = ??? M, V = 25.0 mL.
For Ca(OH)₂, X = 2, M = 1.5 M, V = 45.0 mL.
<em>∴ M of HI = (XMV) Ca(OH)₂ / (XV) HI</em> = (2)(1.5 M)(45.0 mL) / (1)(25.0 mL) = <em>5.4 M.</em>
Answer:
The answer to your question is: letter B.
Explanation:
Carbon atom double-bonded to an oxygen atom C= O,
a) Carbohydrate group this group does not exist
b)Carbonyl group This option is right, carbonyl group is C=O
c) Hydroxyl group This option is incorrect, hydroxyl group is OH, very different from C=O
d) Ketone group Ketone group does not exist, ketones have the same functional group as aldehydes (C=O)
Answer:
6 Electrons r smaller than a proton or a neutron
Explanation:
D air.......,..........,.......
