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Maslowich
3 years ago
11

What are the two main types of energy?In an illustration, lines of force are drawn around a magnet to illustrate the magnetic

Chemistry
1 answer:
gladu [14]3 years ago
5 0
Potential and kinetic
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What is einsteins theory of relativity?
White raven [17]

Answer:

The laws of the universe are for all observers, and it was shown that the velocity of light in spacetime will be the same regardless of the subject's speed.

Explanation:

The principle outlines how things behave in time and space, so it could be used to model anything from black hole life to light shifting due to the gravitational, as well as the action of the terrestrial Planets in its orbit. Einstein's most popular hypothesis has far-reaching ramifications.

6 0
3 years ago
Which statement about earths atmosphere is true
satela [25.4K]

Answer: The earth's atmosphere gets thinner with the increase in altitude. The earth's atmospheric layers are Troposphere, Stratosphere, Mesosphere, Ionosphere .

Explanation:

Good luck!

4 0
3 years ago
A sample of neon gas occupies 0.220L at 0.860atm. What will be it’s new volume at 1.52 atm, assuming the temperature remains con
kramer
 The  new   volume  at 1.52 atm  is calculated  by  use  of  Bolyes  law  formula

that is  P1V1=P2V2
V1 = 0.220 L
P1=  0.860  atm
P2 =1.52  atm
V2=?

V2  is therefore = P1V1/P2

=(0.220 L x 0.860  atm)/ 1.52 atm= 0.1245  Liters

8 0
3 years ago
1. Determine the molarity given 0.6762 mol KOH and a volume of<br> 500.00 mL.
astra-53 [7]

Answer:

1.352 M

Explanation:

Molarity is equal to the moles of the substance divided by the volume in Liters. First convert mL to L. 500.00 mL is 0.50000 L. Divide 0.6762 by 0.5 and remember to keep a maximum of 4 significant figures. :)

8 0
3 years ago
What is the wavenumber of the radiation emitted when a hydrogen
LUCKY_DIMON [66]

Answer: Wavenumber of the radiation emitted  is 0.08\times 10^{8}m^{-1}

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

E=\frac{hc}{\lambda}

where,

E = energy of the radiation = 1.634\times 10^{-18}J

h = Planck's constant  = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of radiation = ?

Putting values in above equation, we get:

1.634\times 10^{-18}J=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{\lambda}\\\\\lambda=12.16\times 10^{-8}m

\bar {\nu}=\frac{1}{\lambda}=\frac{1}{12.16\times 10^{-8}}=0.08\times 10^{8}m^{-1}

Thus wavenumber of the radiation emitted  is 0.08\times 10^{8}m^{-1}

8 0
4 years ago
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