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inysia [295]
3 years ago
11

7+8r+10r pls help me im failing

Mathematics
1 answer:
Umnica [9.8K]3 years ago
4 0

Final Answer: 7 + 18r

Steps/Reasons/Explanation:

Question: Solve 7 + 8r + 10r.

<u>Step 1</u>: Collect like terms.

7 + (8r + 10r)

<u>Step 2</u>: Simplify.

7 + 18r

~I hope I helped you :)~

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Solve |-x+ 5| = |3x – 3| by graphing.
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your points should be -1 and 2

Step-by-step explanation:

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I actually don’t get this and I have a test in 2 days please help what is g(x) and how
nataly862011 [7]

first off, is noteworthy that's the graph of an exponential function, thus the function will be along the lines of g(x) = abˣ , now, what's "a" and "b" values?

well, let's take a peek when x = 0 and x = 1.

\bf g(x) = ab^x \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} x = 0\\ y = 1 \end{cases}\implies 1=ab^0\implies 1=a(1)\implies \boxed{1=a} \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} x = 1\\ y = 4 \end{cases}\implies 4 = ab^1\implies 4=1b^1\implies \boxed{4=b} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill g(x) = 4^x\qquad \qquad \qquad \begin{array}{|c|c|ll} \cline{1-2} x&y\\ \cline{1-2} -2&\frac{1}{4^2}\to \frac{1}{16}\\ -1&\frac{1}{4}\\ 0&1\\ 1&4\\ 2&16\\ \cline{1-2} \end{array}~\hfill

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(−9a+4b)^2 10000 Points for Brainliest Answer!!!!
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a cell phone company plans to market a new smartphone. they have already sold 612 units durning the first week of the campaign.
Vadim26 [7]

The first term is 612.

The common ratio is 1.08 and

The recursive rule is a_{n} = a^{n-1} \times r

<u>Step-by-step explanation:</u>

the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.

<u>The first term :</u>

In geometric sequence, the first term is given as a_{1}.

⇒ a_{1} = 612

Now, the geometric sequence follows as 612, 661, ........

<u>The common ratio (r) :</u>

It is the ratio between two consecutive numbers in the sequence.

Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence.

⇒ r = 661 divided by 612

⇒ r = 1.08

<u>To find the recursive rule :</u>

A geometric series is of the form  a,ar,ar2,ar3,ar4,ar5........

Here, first term a_{1} = a and other terms are obtained by multiplying by r.

  • Observe that each term is r times the previous term.
  • Hence to get nth term we multiply (n−1)th term by r .

The recursive rule is of the form a_{n} = a^{n-1} \times r

This is called recursive formula for geometric sequence.

We know that r = 1.08 and a_{1} = 612.

To find the second term a_{2}, use the recursive rule a_{n} = a^{n-1} \times r

⇒ a_{2} = a^{2-1}\times r

⇒ a_{2} = a^{1}\times r

⇒ a_{2} = 612\times 1.08

⇒ a_{2} = 661

3 0
3 years ago
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