What is YZ? Enter your answer as a decimal in the box.
1 answer:
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Answer:
Step-by-step explanation:
A circle centered at (0,0) with radius r is
Since your circle has diameter of 12, then its radius is 6. Then
So a possible answer is:
If you want to move the location of the center, but keep it on the x-axis, then add or subtract a number to the x, such as this:
The center of this circle would be (-4, 0) which is still on the x-axis.
Answer:
x = π/3, x = 5π/3, x = 4π/3
Step-by-step explanation:
Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3 = 0.
Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.
Similarly:
The general solutions for sin(x) = - √3/2 are x = 4π/3 + 2πn and x = 5π/3 + 2πn. Therefore x = 4π/3 and x = 5π/3 in this case.
So we have x = π/3, x = 5π/3, and x = 4π/3 as our solutions.