Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate


L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
Answer:
Step-by-step explanation:
(A)
A=hw, h=1.5w
A=1.5w^2
(B)
A=(h+8)(w+8), h=1.5w
A=(1.5w+8)(w+8)
A=1.5w^2+12w+8w+64
A=1.5w^2+20w+64
Answer:
either 2 or 1/2, depending on what the original shape was
Step-by-step explanation:
going from small to large it is clearly visible that 3 units of side length turn into 6 units. so, the scaling factor is 2.
going from large to small it is clear that 6 units of side length turn into 3 units. so, the scaling factor is 1/2.
There are 7 fruit bars left from each box
9514 1404 393
Answer:
10x^6
Step-by-step explanation:
The applicable rule of exponents is ...
(a^b)(a^c) = a^(b+c)
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