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2 years ago

1.what is definition and

Mathematics

1 answer:

lorasvet [3.4K]2 years ago

5 0

Answer:

1..ans- kite is a quadrilateral in which two disjoint pairs of consecutive sides are congruent (“disjoint pairs” means that one side can't be used in both pairs). ... The opposite angles at the endpoints of the cross diagonal are congruent (angle J and angle L).

You might be interested in

Round this number to nearest 10,000. 4,278,003

s2008m [1.1K]

Hi there!

To Round of the number given, first you have to find the ten thousands place on the given number. Started from ones, tens, hundreds, and moving on, the number in the ten thousands place would be 7 in your case.

Now, looking to the number on the right of 7 which is 8, it is bigger than 5, and therefore, we round up 7 and let 8 go to zero.

Applying this, your answer would be 4,280,003

Hope this helped!

4 0

3 years ago

Read 2 more answers

9.3.2 Listed below are body temperatures from five different subjects measured at 8 AM and again at 12 AM. Find the values of d

kotegsom [21]

Answer:

$\frac{}{d}$ = −0.26

$s_{d}$ = 0.4219

Step-by-step explanation:

Given:

Sample1: 98.1 98.8 97.3 97.5 97.9

Sample2: 98.7 99.4 97.7 97.1 98.0

Sample 1 Sample 2 Difference d

98.1 98.7 -0.6

98.8 99.4 -0.6

97.3 97.7 -0.4

97.5 97.1 0.4

97.9 98.0 -0.1

To find:

Find the values of $\frac{}{d}$ and $s_{d}$

d overbar ( $\frac{}{d}$ ) is the sample mean of the differences which is calculated by dividing the sum of all the values of difference d with the number of values i.e. n = 5

$\frac{}{d}$ = ∑d/n

= (−0.6 −0.6 −0.4 +0.4 −0.1) / 5

= −1.3 / 5

$\frac{}{d}$ = −0.26

s Subscript d is the sample standard deviation of the difference which is calculated as following:

$s_{d}$ = √∑( $d_{i}$ - $\frac{}{d}$ )²/ n-1

$s_{d}$ =

√ $(-0.6 - (-0.26))^{2} + (-0.6 - (-0.26))^{2} + (-0.4 - (-0.26))^{2} + (0.4-(-0.26))^{2} + (-0.1 - (-0.26))^{2} / 5-1$

= √ (−0.6 − (−0.26 ))² + (−0.6 − (−0.26))² + (−0.4 − (−0.26))² + (0.4 −

(−0.26))² + (−0.1 − (−0.26))² / 5−1

= $\sqrt{\frac{0.1156 + 0.1156 + 0.0196 + 0.4356 + 0.0256}{4} }$

= $\sqrt{\frac{0.712}{4} }$

= $\sqrt{0.178}$

= 0.4219

$s_{d}$ = 0.4219

Subscript d represent

μ $_{d}$ represents the mean of differences in body temperatures measured at 8 AM and at 12 AM of population.

3 0

3 years ago

Its asking to solve for y and the rest

gladu [14]

First you have to find the missing y

3 0

3 years ago

The radius of the tires of a car is 18 inches, and they are revolving at the rate of 651 revolutions per minute. How fast is the

Mumz [18]

So the car is moving at 651 revolutions per minute, with wheels of a radius of 18inches

so, one revolution, is just one go-around a circle, and thus 2π, 651 revolutions is just 2π * 651, or 1302π, the wheels are moving at that "angular velocity"

now, what's the linear velocity, namely, the arc covered per minute

well $\bf v=rw\qquad 
\begin{cases}
v=\textit{linear velocity}\\
r=radius\\
w=\textit{angular velocity}\\
----------\\
r=18in\\
w=1302\frac{\pi }{min}
\end{cases}\implies v=18in\cdot \cfrac{1302\pi }{min}
\\\\\\
v=\cfrac{23436\pi\ in}{min}$

now, how much is that in miles/hrs? well
let's keep in mind that, there are 12inches in 1foot, and 5280ft in 1mile, whilst 60mins in 1hr

thus $\bf \cfrac{23436\pi\ in}{min}\cdot \cfrac{ft}{12in}\cdot \cfrac{mi}{5280ft}\cdot \cfrac{60min}{hr}\implies \cfrac{23436\cdot \pi \cdot 60\ mi}{12\cdot 5280\ hr}$

notice, after all the units cancellations, you're only left with mi/hrs

4 0

3 years ago

As the number of degrees of freedom for a t distribution increases. True or False

valkas [14]

Answer:

t distribution behaves like standard normal distribution as the number of freedom increases.

Step-by-step explanation:

The question is missing. I will give a general information on t distribution.

t-distribution is used instead of normal distribution when the <em>sample size is small (usually smaller than 30) </em>or <em>population standard deviation is unknown</em>.

Degrees of freedom is the number of values in a sample that are free to vary. As the number of degrees of freedom for a t-distribution increases, the distribution looks more like normal distribution and follows the same characteristics.

7 0

3 years ago