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N76 [4]
3 years ago
6

3.5b + 6.8k - 5.2b - 2.3k

Mathematics
2 answers:
Likurg_2 [28]3 years ago
6 0

Answer:

−1.7b+4.5k

Step-by-step explanation:

First, combine like terms.

Subtract 3.5b and  

3.5b + 6.8k + −5.2b + −2.3k

=(3.5b+ −5.2b) + (6.8k + −2.3k)

Then you should get an answer of 1.7b+4.5k.

I hope this helps :)

SVEN [57.7K]3 years ago
4 0

Answer:

− 1.7b + 4.5k is the simplified equation. Is that the answer you were looking for?

Step-by-step explanation:

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Laura left Dunkin Donuts at 1 PM traveling 30 mph. Two hours later her friend Jen left the same Dunkin Donuts and started after
Wewaii [24]

Answer:

It took Jen 4 hours to catch up with Laura

Step-by-step explanation:

Gaining speed 45-30= 15 mph

Laura's head start 30×2=60 miles

Time for Jen to catch up 60÷15= 4 hours

In other words

30(t+2)= 45t

30t+60= 45t

60=45t-30t

60= 15t

t=4 hours

5 0
3 years ago
Find the values of p and q such that 4x^2+12x=4(x+p)^2-q
-Dominant- [34]

Answer:

p = 1.5 and q = 9

Step-by-step explanation:

Expand the right side then compare the coefficients of like terms on both sides, that is

4(x + p)² - q ← expand (x + p)² using FOIL

= 4(x² + 2px + p²) - q ← distribute parenthesis

= 4x² + 8px + 4p² - q

Comparing coefficients of like terms on both sides

8p = 12 ( coefficients of x- terms ) ← divide both sides by 8

p = 1.5

4p² - q = 0 ( constant terms ), that is

4(1.5)² - q = 0

9 - q = 0 ( subtract 9 from both sides )

- q = - 9 ( multiply both sides by - 1 )

q = 9

7 0
3 years ago
A right triangle has one leg with a length of 48 and a hypotenuse with a length of 80. What is the length of the other leg?
Fofino [41]
Pythagoras Theroem.
Leg₁²+leg₂²=hypotenuse²

Data:
Leg₁=48
hypotneuse=80

(48)²+ leg₂²=(80)²
2304+leg₂²=6400
leg₂²=6400-2304
leg₂²=4096
leg₂=√4096
leg₂=64

Answer: B.  64
8 0
3 years ago
A publisher requires 2⁄3 of a page of advertisements for every 5 pages in a magazine. If a magazine has 98 pages, to the nearest
rjkz [21]

Let x be the number of pages of advertisements.

Write a proportion from the table:

\dfrac{2}{3} of a page of advertisment - 5 pages in a magazine

x pages of advertisment - 98 pages in a magazine,

then

\dfrac{\dfrac{2}{3}}{x}=\dfrac{5}{98}.

Find x:

x=\dfrac{\dfrac{2}{3}\cdot 98}{5}=\dfrac{196}{15}=13\dfrac{1}{13}.

Answer: 13 whole pages and \dfrac{1}{13} of 14th page are advertisments, so 14 pages contain advertisments.

3 0
3 years ago
Please Help me this is the first part of 4 in this question. I will be posting the other 3 shortly. I need the answer. This is v
Ket [755]

Answer:

y = 1/6x + 5

Step-by-step explanation:

-x + 6y = 30

6y = x + 30

y = 1/6x + 5

6 0
2 years ago
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