You can use the following equation:
10h+3p+0.5r=100
This equation uses “h” “p” and “r” to represent the number of animals bought, each variable having a coefficient which is that animal's price. The right side is the total price.
You will now need a second equation so you can proceed to substitution/elimination:
h+p+r=100
This equation, using the same variables, represents the total number of animals to be bought.
We can eliminate the “h” variable by multiplying the bottom equation by -10, you now have the following:
10h+3p+0.5r=100
-10h-10p-10r=-1000
Add down and the result is:
-7p-9.5r=-900
You can set up a proportion
-9.5r=-900+7p
r=(-900+7p)/-9.5
And substitute in the original equation…
P.S. I challenge you to figure out the rest on your own because it is really just a tedious process of substitution and elimination from here and my phone is about to die. I'll check in later if you're still having problems.
Answer:
slope = 3
Step-by-step explanation:
5 - x1 -5 - y1
-1- x2 7 - y2
m= y2 - y1 / x2 - x1
m= 7 - (-5) / -1 -(-5)
m= 12 / 4
m= 3
3x³×y²×12x²×y×z=36x⁵×y³×z
We have:
(30x²+23x+16)/(cx+3) - 13/(cx+3) = 6x+1
(30x²+23x+16 - 13)/(cx+3) = 6x+1
(30x²+23x+3)/(cx+3) = 6x+1
30x²+23x+3 = (cx+3)(6x+1)
30x²+23x+3 = 6cx²+cx+18x+3
30x² + 23x + 3 - 6cx² - cx - 18x - 3 = 0
(30 - 6c)x² +(5 - c)x = 0
6(5 - c)x² +(5 - c)x = 0
(5 - c)(6x² +x) = 0, and x∈ R\ {3/c} ⇒ 5 - c = 0 ⇒ c = 5.
