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Genrish500 [490]
3 years ago
10

9c- 3z = 3(___c- ___z)

Mathematics
2 answers:
Scilla [17]3 years ago
8 0

Answer:

3(3c-z)

Step-by-step explanation:

hope this was helpful let me know if you need the steps!! <3

Vladimir79 [104]3 years ago
4 0

Answer:

3 and 1

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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2 years ago
Which models show the problem 4
exis [7]

Answer:

the second and last sentences.

Step-by-step explanation:

Its the most reasonable!

7 0
3 years ago
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1 2 3 4 5 6 7 8 9 10 TIME REMAINING 52:51 Use the data set to determine which statements are correct. Check all that apply. 35,
Nady [450]

Answer:

The true statements are:

  • The median is 38.5.
  • There is an outlier.
  • The lower quartile is 29.
  • The upper quartile is 70.
  • The interquartile range is 41.

Step-by-step explanation:

The given data are:  35, 41, 18, 75, 36, 21, 62, 29, 154, 70

Make the data in order from the least to the greatest

18 , 21 , 29 , 35 , <u>36 , 41</u> , 62 , 70 , 75 , 154

So, the median of the data = (36 + 41)/2 = 38.5

We can deduce that The number 154 represents an outlier because the difference between 154 and 75 is much greater than the difference between the other data

If we divided the data to two groups , they will be:

(18 , 21 , <u>29 </u>, 35 , 36)  ,  (41 , 62 , <u>70 </u>, 75 , 154)

So, The lower quartile Q1 is the median of the first group = 29

And the upper quartile Q2 is the median of the second group = 70

And the interquartile range = Q2 - Q1 = 70 - 29 = 41

So, the true statements are:

  • The median is 38.5
  • There is an outlier
  • The lower quartile is 29
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  • The interquartile range is 41.
7 0
3 years ago
A movie ticket is $12 plus an 8.5% sales tax how much for one movie ticket cost
yarga [219]
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4 0
3 years ago
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Wholesale cost of a telescope: $199.50; Markup: 50%, Discount: 30%,
kupik [55]

Answer:

$2147.85

Step-by-step explanation:

199.5*.5=99.75

199.5+99.75=299.25

299.25*.3=89.775

299.25-89.775=209.475

209.475*.04=8.279

209.475+8.379=217.854

7 0
3 years ago
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