The simplest (and most commonly used) area calculations are for squares and rectangles. To find the area of a rectangle, multiply its height by its width. For a square you only need to find the length of one of the sides (as each side is the same length) and then multiply this by itself to find the area.

3 0

3 years ago

Math Question :

saw5 [17]

Let x = amount of mortgage (aka the amount by the bank)

25% of the monthly income of $3000 is 0.25*3000 = 750 dollars

So using this rule, the family can pay up to $750 per month on mortgage

1% of the amount loaned (x) is equal to this figure, so

0.01*x = 750
0.01*x/0.01 = 750/0.01
x = 75000

Therefore, the most expensive mortgage this family can afford is $75,000. Anything higher and they go over budget.

7 0

3 years ago

A particle moves along the curve below. y = √ 8 + x 3 As it reaches the point ( 1 , 3 ) , the y -coordinate is increasing at a r

Dmitry [639]

Answer:

The x-coordinate is changing at 10 cm/s

Step-by-step explanation:

Rate of Change

Suppose two variables x and y are related by a given function y=f(x). If they both change with respect to a third variable (time, for instance), the rate of change of them is computed as the derivative using the chain rule:

$\displaystyle \frac{dy}{dt}=\frac{dy}{dx}\cdot \frac{dx}{dt}$

We have

$y=\sqrt{8+x^3}$

Or, equivalently

$y^2=8+x^3$

We need to know the rate of change of x respect to t. We'll use implicit differentiation:

$\displaystyle 2y\cdot \frac{dy}{dt}=3x^2\cdot \frac{dx}{dt}$

Solving for dx/dt

$\displaystyle \frac{dx}{dt}=\frac{2y\cdot \frac{dy}{dt}}{3x^2}$

Plugging in the values x=1, y=3, dy/dt=5

$\displaystyle \frac{dx}{dt}=\frac{2(3)\cdot 5}{3\cdot 1^2}=10$

The x-coordinate is changing at 10 cm/s

7 0

3 years ago

Please answer this correctly

iren2701 [21]

Answer:

$10.71 yd$

Step-by-step explanation:

First let's find the radius of the quarter circle.

$area =\frac{1}{4} \pi {r}^{2} \\ 7.065 = \frac{1}{4} *3.14 {r}^{2} \\ \frac{7.065}{3.14} = \frac{1}{4} * \frac{3.14 {r}^{2} }{3.14} \\ 9 = {r}^{2} \\ \sqrt{9} = r \\ 3 yd= r$

Now let's find the arc length of this quarter circle.

$\frac{90}{360} \times 2\pi \: r \\ \frac{1}{4} \times 2 \times 3.14 \times 3 \\ = \frac{9.42}{4} \\ = 4.71yd \\$

Now let's find the perimeter $perimeter \\ = arc \: \: length + radius + radius \\ = 4.71 + 3 + 3 \\ = 10.71yd$

hope this helps

brainliest appreciated

good luck! have a nice day!

4 0

3 years ago

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