Answer:
93% probability of a student taking a calculus class or a statistics class
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
A is the probability that a student takes a calculus class.
B is the probability that a student takes a statistics class.
We have that:

In which a is the probability that a student takes calculus but not statistics and
is the probability that a student takes both these classes.
By the same logic, we have that:

The probability of taking a calculus class and a statistics class is 0.07
This means that 
The probability of taking a statistics class is 0.90
This means that
. So



The probability of a student taking a calculus class is 0.10
This means that 



What is the probability of a student taking a calculus class or a statistics class

93% probability of a student taking a calculus class or a statistics class
Answer:
x=12
Step-by-step explanation:
each CD is 12$
Answer:
Step-by-step explanation:
Multiply $120 (cost of haircut) X .18 (18% in decimal form) to get the tip amt.
120 X .18 = 21.60
Now add $120 (haircut) + 21.60 (tip) together to get the total amt. she paid.
120 + 21.60 = $131.60
Carla gave her stylist $131.60 total
No solution but the equation is true
It would be 224 , the base is 64 and every triangle is 80 but if you follow the rule for area to a triangle you get 40
So 64+40+40+40+40= 224