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dedylja [7]
2 years ago
15

Please answer the second question what does it mean and is it realistic

Mathematics
1 answer:
frutty [35]2 years ago
4 0

Answer:

The more staff there is, the lower the wait time. Yes, this is realistic.

Step-by-step explanation:

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It is a well-known fact that 50% of the general population are rascals (P(R) = 0.5) and 50% of the general population are not ra
aleksley [76]

Answer:

The answer is D. 0.75

Step-by-step explanation:

Let call R the event that a person is rascal, RC a person is not rascal, TH a person use top hat and NTH a person don’t use top hat.  

From the information on the question we have 4 options with their respective probability:

1. A person could be rascal and use top Hat: this probability is calculate as the multiplication of the probability of be a rascal (0.5) and use a top hat (0.9), then:

P(R y TH)=0.5*0.9=0.45

2. A person could be rascal and don’t use top Hat: this probability is calculate as the multiplication of the probability of be a rascal (0.5) and not use a top hat (0.9), then:

P(R y NTH)=0.5*0.1=0.05

3. A person could be not rascal and use top Hat: this probability is calculate as the multiplication of the probability of not be a rascal (0.5) and use a top hat (0.3), then:

P(RC y TH)=0.5*0.3=0.15

4. A person could be not rascal and not use top Hat: this probability is calculate as the multiplication of the probability of not be a rascal (0.5) and not use a top hat (0.7), then:

P(RC y NTH)=0.5*0.7=0.35

Then the probability that a person is a rascal given that he is wearing a top hat could be written and calculate as:

P(R/TH)=\frac{P(R y TH)}{P(TH)}

For calculate P(TH) we need to sum all the option in which TH is involve so:

P(TH) = P(R y TH)+ P(RC y TH)

P(TH)=0.45+0.15=0.6

Replacing values on the first equation we get:

P(R/TH)=\frac{0.45}{0.6} =0.75

So, the probability that a person is a rascal given that he is wearing a top hat is 0.75

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