Answer:
Slope of line = 
Slope of parallel line = 
Slope of perpendicular line = (-2)
Step-by-step explanation:
Slope of a line passing through two points
and
is,

Therefore, equation of a line passing through points (1, -3) and (-1, -4) will be,


If the slope of a line parallel to the given line is
,
Then by the property of parallel lines,

Therefore, slope of the parallel line will be
.
Property of perpendicular lines,



Therefore, slope of the perpendicular line will be (-2).