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2 years ago

8

A shopkeeper bought a television for Rs. 10000 and he sold it at profit of 25%. What was the selling price of the television? Pl

zz help with this question!!

1 answer:

-Dominant- [34]2 years ago

6 0

Answer:

12,500

Step-by-step explanation:

125%/100% x 10000

12,500

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Nine workers are hired to weed a field by

Dmitriy789 [7]

Answer:

144

Step-by-step explanation:

12x12=144

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3 years ago

a restaurant sells a coffee refill mug for $6.75. Each refill costs $1.25. Last month keith spent $31.75 on a mug and refills wr

evablogger [386]

y= 1.25x+6.75
Make 31.75 y because that is the total cost he paid.
1.25x+6.75=31.75
1.25x=25
x=20
So he had 20 refills.

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3 years ago

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the graph shows the total number of comic books in brandon's collection at the end of every month for the year 2014

saw5 [17]

Answer:

B

Step-by-step explanation:

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2 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

4 0

2 years ago

Can some one do all these questions for me.

Zielflug [23.3K]

Which questions can you please send a link? :)

6 0

3 years ago