2 years ago

Factor completely 21x^3+35x^2+9x+15

Mathematics

1 answer:

Soloha48 [4]2 years ago

7 0

Answer:

(3x+5)(7x^2+3)

Step-by-step explanation:

Factor : 21x^3+35x^2+9x+15

21x^3+35x^2+9x+15

=(3x+5)(7x^2+3)

______________________

Hope this helps!

You might be interested in

Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4

steposvetlana [31]

$f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}$

$\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}$

6 0

3 years ago

Read 2 more answers

Please help I need it please please

Anni [7]

Answer:

23 %

Step-by-step explanation:

151.34 ÷ 658 × 100

hope this helps

have a nice day <3

6 0

2 years ago

Read 2 more answers

The Candy Shack sold 138 pounds of candy on Tuesday 52% of candy was Jellybeans how many pounds of jelly beans were sold Tuesday

erik [133]

Answer:

72 jelly beans

Step-by-step explanation:

138*0.52=71.76

round up

7 0

3 years ago

Cost of a Shirt increased from $10 to $30.What is the percent change?

Alexeev081 [22]

200% bc it went up 2x as much as it cost before

4 0

3 years ago

Read 2 more answers

Solve the equation 3y-9x=-3

ipn [44]

This equation can have a number of solutions. Typically when solving a two-variable equation, you are looking for the slope intercept form of the line. In this case that is:

y = 3x - 1

7 0

3 years ago