Answer:
Step-by-step explanation:
Your friend has a head start of (2 h)×(8 mi/h) = 16 mi.
When you leave, you gain on your friend at the rate of 40 mph - 8 mph = 32 mph. So, it will take ...
(16 mi)/(32 mi/h) = 1/2 h
for you to reduce the distance between you to zero.
In that 1/2 hour, you have traveled ...
(1/2 h)×(40 mi/h) = 20 mi
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This is the same distance your friend has traveled in 2.5 hours at 8 mi/h.
Answer:
20
Step-by-step explanation:
260/13=20
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Oldest = 2 times Youngest -> O = 2*Y
Middle = Youngest + 5 -> M = Y+5
All of them together is 57 -> O + M + Y = 57
So you have these three equations:
(1) O = 2*Y
(2) M = Y+5
(3) O + M + Y = 57
Now you want to reduce the number of variables. You can change the second equation to be Y = M-5 and then plug in "M-5" wherever there is currently a Y:
(4) O = 2*(M-5) = 2*M - 10
(5) O + M + (M-5) = 57
which becomes O + 2M = 62
Then you plug in the "O" equation (4) into (5) which gives you
(2M-10) + 2M = 62 which reduces to 4M = 72.
So now I know M is 18.
I can now plug that into my other equations:
(4) O = 2*18 - 10 which means O = 26.
Now I plug that into (1) from the top:
26 = 2*Y which becomes 13 = Y
So now I have O, Y, and M
Oldest is 26
Middle is 18
Youngest is 13
Reading the sentence again, you can see that this makes sense.
Answer:
https://cougar.collegiate-va.org/cfoster/Mrs._Fosters_Classes/Algebra_1_files/0437_001.pdf
Step-by-step explanation: go to the 3rd page of link
