Question

Check this (1+i)^10)=32i

Answer 1

Answer:

I agree with your result

(1 + i)¹⁰ = 32i

Step-by-step explanation:

(1 + i)² = (1 + i)(1 + i) = 1 + 2i - 1 = 2i

(1 + i)⁴ = 2i(2i) = -4

(1 + i)⁸ = -4(-4) = 16

(1 + i)¹⁰ = (1 + i)⁸((1 + i)² = 16(2i) = 32i